在ORACLE数据库应用调优中,一个SQL的执行次数/频率也是常常需要关注的,因为某个SQL执行太频繁,要么是由于应用设计有缺陷,需要在业务逻辑上做出优化处理,要么是业务特殊性所导致。如果执行频繁的SQL,往往容易遭遇一些并发性的问题。 那么如何查看ORACLE数据库某个SQL的执行频率/次数呢? 下面来看看完整的示例代码。
一、查询执行最慢的sql
1 select * 2 from (select sa.SQL_TEXT, 3 sa.SQL_FULLTEXT, 4 sa.EXECUTIONS "执行次数", 5 round(sa.ELAPSED_TIME / 1000000, 2) "总执行时间", 6 round(sa.ELAPSED_TIME / 1000000 / sa.EXECUTIONS, 2) "平均执行时间", 7 sa.COMMAND_TYPE, 8 sa.PARSING_USER_ID "用户ID", 9 u.username "用户名", 10 sa.HASH_VALUE 11 from v$sqlarea sa 12 left join all_users u 13 on sa.PARSING_USER_ID = u.user_id 14 where sa.EXECUTIONS > 0 15 order by (sa.ELAPSED_TIME / sa.EXECUTIONS) desc) 16 where rownum <= 50;
二、查询次数最多的 sql
1 select * 2 from (select s.SQL_TEXT, 3 s.EXECUTIONS "执行次数", 4 s.PARSING_USER_ID "用户名", 5 rank() over(order by EXECUTIONS desc) EXEC_RANK 6 from v$sql s 7 left join all_users u 8 on u.USER_ID = s.PARSING_USER_ID) t 9 where exec_rank <= 100;
三、Oracle查询SQL语句执行的耗时
1 select a.sql_text SQL语句, 2 b.etime 执行耗时, 3 c.user_id 用户ID, 4 c.SAMPLE_TIME 执行时间, 5 c.INSTANCE_NUMBER 实例数, 6 u.username 用户名, a.sql_id SQL编号 7 from dba_hist_sqltext a, 8 (select sql_id, ELAPSED_TIME_DELTA / 1000000 as etime 9 from dba_hist_sqlstat 10 where ELAPSED_TIME_DELTA / 1000000 >= 1) b, 11 dba_hist_active_sess_history c, 12 dba_users u 13 where a.sql_id = b.sql_id 14 and u.username = 'POADB' 15 and c.user_id = u.user_id 16 and b.sql_id = c.sql_id 17 and a.sql_text like '%insert into TTTTTT %' 18 order by SAMPLE_TIME desc, 19 b.etime desc;
四:定位系统里面哪些SQL脚本存在TABLE ACCESS FULL行为
1 select * from v$sql_plan v 2 where v.operation = 'TABLE ACCESS' 3 and v.OPTIONS = 'FULL' 4 and v.OBJECT_OWNER='POSDB';
1 select s.SQL_TEXT from v$sqlarea s 2 where s.SQL_ID = '4dpd97jh2gzsd' 3 and s.HASH_VALUE = '1613233933' 4 and s.PLAN_HASH_VALUE = '3592287464'; 5 6 /*或者*/ 7 select s.SQL_TEXT from v$sqlarea s where s.ADDRESS ='00000000A65D2318';