zoukankan      html  css  js  c++  java
  • 九度OJ 1143:Primary Arithmetic(初等数学) (进位)

    时间限制:1 秒

    内存限制:32 兆

    特殊判题:

    提交:616

    解决:254

    题目描述:

        Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the "carry" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty. 

    输入:

        Each line of input contains two unsigned integers less than 10 digits. The last line of input contains 0 0.

    输出:

        For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.

    样例输入:
    123 456
    555 555
    123 594
    0 0
    样例输出:
    NO carry operation.
    3 carry operations.
    1 carry operation.
    来源:
    2009年北京大学计算机研究生机试真题


    思路:

    求两数相加的进位次数。


    代码:

    #include<stdio.h>
    int a,b;
    int main()
    {
            while(scanf("%d%d",&a,&b)!=EOF)
            {
                    int c=0;
                    int k=0;
                    if(a==0&&b==0)
                            break;
                    while(a!=0&&b!=0)
                    {
                            c=(a%10+b%10+c)/10;
                            if(c>=1)
                                    k++;
                            a/=10;
                            b/=10;
                    }
                    if(k==0)
                            printf("NO carry operation.
    ");
                    else if(k==1)
                            printf("%d carry operation.
    ",k);
                    else
                            printf("%d carry operations.
    ",k);
            }
             
            return 0;
    }
    /**************************************************************
        Problem: 1143
        User: liangrx06
        Language: C
        Result: Accepted
        Time:0 ms
        Memory:912 kb
    ****************************************************************/
    


    编程算法爱好者。
  • 相关阅读:
    Debugging Auto Layout:Ambiguous Layouts
    Debugging Auto Layout:Unsatisfiable Layouts
    Debugging Auto Layout
    Auto Layout Cookbook:Views with Intrinsic Content Size
    编译地址与运行地址
    Memory Controller
    ARM寄存器
    C++指针悬挂(赋值运算符重载)
    多态性,友元与静态成员 基础知识小结
    ARM 汇编指令集
  • 原文地址:https://www.cnblogs.com/liangrx06/p/5083888.html
Copyright © 2011-2022 走看看