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  • [LeetCode]-DataBase-Employees Earning More Than Their Managers

    The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

    +----+-------+--------+-----------+
    | Id | Name  | Salary | ManagerId |
    +----+-------+--------+-----------+
    | 1  | Joe   | 70000  | 3         |
    | 2  | Henry | 80000  | 4         |
    | 3  | Sam   | 60000  | NULL      |
    | 4  | Max   | 90000  | NULL      |
    +----+-------+--------+-----------+
    

    Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

    +----------+
    | Employee |
    +----------+
    | Joe      |
    +----------+

    要求:查询出表中工资比经理高的员工姓名

    查询一:

    CREATE TABLE `employee` (
    `id` tinyint(3) unsigned DEFAULT NULL,
    `e_name` varchar(20) DEFAULT NULL,
    `salary` decimal(10,2) DEFAULT NULL,
    `m_id` tinyint(3) unsigned DEFAULT NULL
    ) ENGINE=MyISAM DEFAULT CHARSET=utf8;

    SELECT em1.e_name
    FROM(SELECT id,e_name,salary,m_id FROM employee_1 WHERE m_id IS NOT NULL) em1
    INNER JOIN employee_1 em2 ON em1.m_id=em2.id
    WHERE em1.salary>em2.salary


    查询二:

    SELECT e1.e_name
    FROM employee_1 e1
    INNER JOIN employee_1 e2 ON e1.m_id=e2.id
    WHERE e1.salary>e2.salary





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  • 原文地址:https://www.cnblogs.com/lianliang/p/5303016.html
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