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  • [LeetCode]-011-Integer_to_Roman

    Given an integer, convert it to a roman numeral.

    Input is guaranteed to be within the range from 1 to 3999.

    题目大意:把一个整数转换成罗马数字

     1 public class Solution{
     2     private String[][] arr = {
     3         {"0","I","II","III","IV","V","VI","VII","VIII","IX"},
     4         {"0","X","XX","XXX","XL","L","LX","LXX","LXXX","XC"},
     5         {"0","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"},
     6         {"0","M","MM","MMM"}
     7     };
     8     public String intToRoman(int num) {
     9         if(num<0 || num>3999)
    10             return "";
    11         StringBuilder res = new StringBuilder();
    12         int tmp = num;
    13         if((tmp/1000)!=0)
    14             res.append(arr[3][tmp/1000]);
    15         tmp = tmp%1000;
    16         if((tmp/100)!=0)
    17             res.append(arr[2][tmp/100]);
    18         tmp = tmp%100;
    19         if((tmp/10)!=0)
    20             res.append(arr[1][tmp/10]);
    21         tmp = tmp%10;
    22         if(tmp!=0)
    23             res.append(arr[0][tmp]);
    24         return res.toString();
    25     }
    26     
    27     public static void main(String[] args){
    28         int param = 1234;
    29         if(args.length==1){
    30             param = Integer.valueOf(args[0]);
    31         }
    32         Solution solution = new Solution();
    33         String res = solution.intToRoman(param);
    34         System.out.println(res);
    35     }
    36 }
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  • 原文地址:https://www.cnblogs.com/lianliang/p/5403615.html
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