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  • JSONObject,JSONArray,Map,String之间转换

    http://blog.csdn.net/superit401/article/details/51727739

    1.String转JSONObject

    String jsonMessage = "{"语文":"88","数学":"78","计算机":"99"}";

    JSONObject  myJson = JSONObject.fromObject(jsonMessage);

    2.String转JSONArray

    String jsonMessage = "[{'num':'成绩', '外语':88, '历史':65, '地理':99, 'object':{'aaa':'1111','bbb':'2222','cccc':'3333'}}," +
              "{'num':'兴趣', '外语':28, '历史':45, '地理':19, 'object':{'aaa':'11a11','bbb':'2222','cccc':'3333'}}," +
              "{'num':'爱好', '外语':48, '历史':62, '地理':39, 'object':{'aaa':'11c11','bbb':'2222','cccc':'3333'}}]";
     JSONArray myJsonArray = JSONArray.fromObject(jsonMessage);
     System.out.println(myJsonArray);

    3.String转Map

    (1)

    String jsonMessage = "{"语文":"88","数学":"78","计算机":"99"}";

    JSONObject  myJson = JSONObject.fromObject(jsonMessage);

    Map m = myJson; 

    (2) (需要引入jackjson的core、databind、annotations三个jar包  )

    String json = "{"PayPal key2":"PayPal value2","PayPal key1":"PayPal value1","PayPal key3":"PayPalvalue3"}";  

    ObjectMapper mapper = new ObjectMapper();    
     Map<String,Object> m = mapper.readValue(json, Map.class);  

    (3)(特殊格式的String)

    String a ="{se=2016, format=xml, at=en co=3}";

    a =  a.substring(1, a.length()-1);
    Map docType = new HashMap();  
    Java.util.StringTokenizer items;  
    for(StringTokenizer entrys = new StringTokenizer(a, ", ");entrys.hasMoreTokens();   
    docType.put(items.nextToken(), items.hasMoreTokens() ? ((Object) (items.nextToken())) : null)){  
         items = new StringTokenizer(entrys.nextToken(), "=");  
       }

    4.JSONObject、JSONArray,Map转String

    JSONObject——String:

    System.out.println(myJsonObject);//可直接输出JSONObject的内容

    myJsonObject.toString();

    JSONArray——String:

    System.out.println(myJsonArray);//可直接输出myJsonArray的内容

    myJsonArray.toString();

    Map——String:

    System.out.println(map);//可直接输出map的内容

    map.toString();

    5.JSONObject转JSONArray

    6.JSONObject转Map

    方法一:JSONObject  myJson = JSONObject.fromObject(jsonString);

    Map m = myJson;

    方法二:Map<String, Object> map = (Map<String, Object>) JSONObject.toBean(myJson, Map.class);

    7.JSONArray转JSONObject

      for(int i=0 ; i < myJsonArray.length() ;i++)
       {
        //获取每一个JsonObject对象
        JSONObject myjObject = myJsonArray.getJSONObject(i);

    }

    8.JSONArray转Map

    9.Map转JSONObject

    JSONObject json = JSONObject.fromObject( map );  

    10.Map转JSONArray

     JSONArray.fromObject(map);

    11.List转JSONArray

    JSONArray jsonArray2 = JSONArray.fromObject( list );     

    12.JSONArray转List

    List<Map<String,Object>> mapListJson = (List)jsonArray;

    13.String转数组

    String string = "a,b,c";
    String [] stringArr= string.split(",");  //注意分隔符是需要转译滴...
    如果是"abc"这种字符串,就直接
    String string = "abc" ;
    char [] stringArr = string.toCharArray(); //注意返回值是char数组
    如果要返回byte数组就直接使用getBytes方法就ok了~~
    String string = "abc" ;
    byte [] stringArr = string.getBytes();

    数组转String

    char[] data={a,b,c}; 
    String s=new String(data);

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  • 原文地址:https://www.cnblogs.com/lianxuan1768/p/8366599.html
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