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  • sql查询树(思路)

    --测试数据
    DECLARE @t TABLE(ID char(3),PID char(3),Name nvarchar(10))
    INSERT @t SELECT '001',NULL ,'山东省'
    UNION ALL SELECT '002','001','烟台市'
    UNION ALL SELECT '004','002','招远市'
    UNION ALL SELECT '003','001','青岛市'
    UNION ALL SELECT '005',NULL ,'四会市'
    UNION ALL SELECT '006','005','清远市'
    UNION ALL SELECT '007','006','小分市'
    
    --深度排序显示处理
    --生成每个节点的编码累计(相同当单编号法的编码)
    DECLARE @t_Level TABLE(ID char(3),Level int,Sort varchar(8000))
    DECLARE @Level int
    SET @Level=0
    INSERT @t_Level SELECT ID,@Level,ID
    FROM @t
    WHERE PID IS NULL
    WHILE @@ROWCOUNT>0
    BEGIN
    	SET @Level=@Level+1
    	INSERT @t_Level SELECT a.ID,@Level,b.Sort+a.ID
    	FROM @t a,@t_Level b
    	WHERE a.PID=b.ID
    		AND b.Level=@Level-1
    END
    
    --显示结果
    SELECT SPACE(b.Level*2)+'|--'+a.Name
    FROM @t a,@t_Level b
    WHERE a.ID=b.ID
    ORDER BY b.Sort
    /*--结果
    |--山东省
      |--烟台市
        |--招远市
      |--青岛市
    |--四会市
      |--清远市
        |--小分市
    --*/
    
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  • 原文地址:https://www.cnblogs.com/liaotongquan/p/1533829.html
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