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  • 【老鼠走迷宫二】

    /*
    老鼠走迷宫二 
    有问题 
    */ 
    
    #include <stdio.h>
    #include <stdlib.h>
    
    void visit(int ,int); 
    
    int maze[9][9] = {
        {2, 2, 2, 2, 2, 2, 2, 2, 2}, 
        {2, 0, 0, 0, 0, 0, 0, 0, 2}, 
        {2, 0, 2, 2, 0, 2, 2, 0, 2},
        {2, 0, 2, 0, 0, 2, 0, 0, 2},
        {2, 0, 2, 0, 2, 0, 2, 0, 2},
        {2, 0, 0, 0, 0, 0, 2, 0, 2},
        {2, 2, 0, 2, 2, 0, 2, 2, 2},
        {2, 0, 0, 0, 0, 0, 0, 0, 2},
        {2, 2, 2, 2, 2, 2, 2, 2, 2}
    };
    
    int startI = 1, startJ = 1;
    int endI = 7, endJ = 7;
    
    int main(void)
    {
        int i, j;
        
        printf("显示迷宫: 
    ");
        for(i = 0; i < 9; i++)
        {
            for(j = 0; j < 9; j++)
            {
                if(maze[i][j] == 2)
                    printf("#");
                else
                    printf(" ");
            }
            printf("
    ");
        }
        visit(startI, startJ);
        return 0;
    }
    
    void visit(int i, int j)
    {
        int m, n;
        
        maze[i][j] = 1;
        
        if(i == endI && j == endJ)
        {
            printf("
    显示路径:
    ");
            for(m = 0; m < 9; m++)
            {
                for(n = 0; n < 9; n++)
                {
                    if(maze[m][n] == 2)
                        printf("#");
                    else if(maze[m][n] == 1)
                        printf("$");
                    else
                        printf(" ");
                }
                printf("
    ");
            }
            
        }
        
        if(maze[i][j+1] == 0)
            visit(i, j+1); 
        if(maze[i+1][j] == 0)
            visit(i+1, j);
        if(maze[i][j-1] == 0)
            visit(i, j-1);
        if(maze[i-1][j] == 0)
            visit(i-1, j);
            
        maze[i][j] = 0; 
    }

    运行结果:

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  • 原文地址:https://www.cnblogs.com/libra-yong/p/6391721.html
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