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  • 把自1970年1月1日以来的秒数转化成年月日

    #include <iostream>

    using namespace std;
     
    bool IsRound(int year){
     if((year%100)&&(year%4==0)) return 1;
     if((year%100==0)&&(year%400==0)) return 1;
     return 0;
    }
    int main() {
     int n;
     int year_s[2]= {365*24*60*60, 366*24*60*60};
     int month_s[2][12]={{31,28,31,30,31,30,31,31,30,31,30,31},
       {31,29,31,30,31,30,31,31,30,31,30,31}};
     int day_s = 24*60*60;
     int hour_s = 60*60;
     int minute_s = 60;
     
      
     
     while(cin>>n){
        int temp = n;
        int year=1970;
             int month=1;
             int day=1;
             int hour=0;
             int minute=0;
             int second=0;
     
        while(temp>=60){
     
         int flag= IsRound(year);
         if(temp>=year_s[flag]) { year++; temp-=year_s[flag]; }
         else if(temp>=day_s){
          int days = temp/day_s;
          temp=temp%day_s;
          int i=0;
          int flag = IsRound(year);
          int hh=31;
          while(days>=hh){
           days-=month_s[flag][i++];
           hh=month_s[flag][i];
           }
          month+= i;
          day+=days;
     
         }else if(temp>=hour_s){
              hour=temp/hour_s;
              temp%=hour_s;
         }else if(temp>=minute_s){
               minute = temp/minute_s;
               temp%=minute_s;
         }
         }
         second = temp;
     
            cout<<year<<"-";
          if(month/10==0) cout<<"0";
          cout<<month<<"-";
          if(day/10==0) cout<<"0";
          cout<<day<<" ";
          if(hour/10==0) cout<<"0";
          cout<<hour<<":";
          if(minute/10==0) cout<<"0";
          cout<<minute<<":";
          if(second/10==0) cout<<"0";
          cout<<second<<endl;
     }
     
     
     return 0;
    }
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  • 原文地址:https://www.cnblogs.com/lidabo/p/4499974.html
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