zoukankan      html  css  js  c++  java
  • A1047. Student List for Course (25)

    Zhejiang University has 40000 students and provides 2500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains 2 numbers: N (<=40000), the total number of students, and K (<=2500), the total number of courses. Then N lines follow, each contains a student's name (3 capital English letters plus a one-digit number), a positive number C (<=20) which is the number of courses that this student has registered, and then followed by C course numbers. For the sake of simplicity, the courses are numbered from 1 to K.

    Output Specification:

    For each test case, print the student name lists of all the courses in increasing order of the course numbers. For each course, first print in one line the course number and the number of registered students, separated by a space. Then output the students' names in alphabetical order. Each name occupies a line.

    Sample Input:

    10 5
    ZOE1 2 4 5
    ANN0 3 5 2 1
    BOB5 5 3 4 2 1 5
    JOE4 1 2
    JAY9 4 1 2 5 4
    FRA8 3 4 2 5
    DON2 2 4 5
    AMY7 1 5
    KAT3 3 5 4 2
    LOR6 4 2 4 1 5
    

    Sample Output:

    1 4
    ANN0
    BOB5
    JAY9
    LOR6
    2 7
    ANN0
    BOB5
    FRA8
    JAY9
    JOE4
    KAT3
    LOR6
    3 1
    BOB5
    4 7
    BOB5
    DON2
    FRA8
    JAY9
    KAT3
    LOR6
    ZOE1
    5 9
    AMY7
    ANN0
    BOB5
    DON2
    FRA8
    JAY9
    KAT3
    LOR6
    ZOE1
     1 #include <stdio.h>
     2 #include <stdlib.h>
     3 #include <iostream>
     4 #include <string.h>
     5 #include <string>
     6 #include <math.h>
     7 #include <algorithm>
     8 #include <vector>
     9 using namespace std;
    10 const int maxn=40010;
    11 const int maxc=2510;
    12 
    13 char  name[maxn][5];
    14 vector<int> course[maxc];
    15 
    16 bool cmp(int  a,int b)
    17 {
    18     return strcmp(name[a],name[b])<0;
    19 }
    20  
    21 int main(){
    22     int n,k;
    23     scanf("%d%d",&n,&k);
    24     for(int i=0;i<n;i++)
    25     {
    26         scanf("%s",name[i]);
    27         int r;
    28         scanf("%d",&r);
    29         for(int j=0;j<r;j++)
    30         {
    31             int temp;
    32             scanf("%d",&temp);
    33             course[temp].push_back(i);
    34         }
    35     }
    36     for(int i=1;i<=k;i++)
    37     {
    38         sort(course[i].begin(),course[i].end(),cmp);
    39         printf("%d %d
    ",i,course[i].size()); 
    40         for(int j=0;j<course[i].size();j++)
    41         {
    42             printf("%s
    ",name[course[i][j]]);
    43         }
    44     }
    45     
    46     return 0;
    47 }
  • 相关阅读:
    [工具推荐]005.Axure RP Pro 7.0模拟C#TAB控件
    [安卓基础] 008.Android中的显示单位
    [JavaWeb基础] 008.Spring初步配置
    [批处理教程之Shell]002.Linux 常用命令大全
    [注]新手学习编程的最佳方式是什么?
    [C#打包部署教程]001.VS2012 + InstallShield
    [站点推荐]001.学习新技能的37个最佳网站(The 37 Best Websites To Learn Something New)
    程序员如何像写代码一样找女朋友
    [工具-006] C#如何模拟发包登录
    [Linux系统] (1)常用操作(CentOS 7.x)
  • 原文地址:https://www.cnblogs.com/ligen/p/4306836.html
Copyright © 2011-2022 走看看