zoukankan      html  css  js  c++  java
  • A1088. Rational Arithmetic (20)

    For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient.

    Input Specification:

    Each input file contains one test case, which gives in one line the two rational numbers in the format "a1/b1 a2/b2". The numerators and the denominators are all in the range of long int. If there is a negative sign, it must appear only in front of the numerator. The denominators are guaranteed to be non-zero numbers.

    Output Specification:

    For each test case, print in 4 lines the sum, difference, product and quotient of the two rational numbers, respectively. The format of each line is "number1 operator number2 = result". Notice that all the rational numbers must be in their simplest form "k a/b", where k is the integer part, and a/b is the simplest fraction part. If the number is negative, it must be included in a pair of parentheses. If the denominator in the division is zero, output "Inf" as the result. It is guaranteed that all the output integers are in the range of long int.

    Sample Input 1:

    2/3 -4/2
    

    Sample Output 1:

    2/3 + (-2) = (-1 1/3)
    2/3 - (-2) = 2 2/3
    2/3 * (-2) = (-1 1/3)
    2/3 / (-2) = (-1/3)
    

    Sample Input 2:

    5/3 0/6
    

    Sample Output 2:

    1 2/3 + 0 = 1 2/3
    1 2/3 - 0 = 1 2/3
    1 2/3 * 0 = 0
    1 2/3 / 0 = Inf
    #include <stdio.h>
    #include <stdlib.h>
    #include <algorithm>
    using namespace std;
    
    //求最大公约数
    long long gcd (long long a,long long b)
    {
      if(b==0)return a; 
      else
      {
      return gcd(b,a%b);    
      }
          
    } 
     
     struct Fraction{
         long long up,down;
         }a,b;
         
    Fraction reduction (Fraction res)
    {
        if(res.down<0)
        {
            res.up=-1*res.up;
            res.down=-1*res.down;
        }
        if(res.up==0)
        {
            res.down=1;
            }else
            {
            int d=gcd(abs(res.up),abs(res.down));
            res.up/=d;
            res.down/=d;
            }
         return res;   
    }     
    
    
    Fraction add(Fraction a,Fraction b)
    {
        Fraction res;
        res.down=a.down*b.down;
        res.up=a.up*b.down+a.down*b.up;
        return reduction(res);
        }
    Fraction minusF(Fraction a,Fraction b)
    {
        Fraction res;
        res.down=a.down*b.down;
        res.up=a.up*b.down-a.down*b.up;
        return reduction(res);
        }
    Fraction multi(Fraction a,Fraction b)
    {
        Fraction res;
        res.down=a.down*b.down;
        res.up=a.up*b.up;
        return reduction(res);
        }
    
    Fraction divide(Fraction a,Fraction b)
    {
        Fraction res;
        res.down=a.down*b.up;
        res.up=a.up*b.down;
        return reduction(res);
        }
    
    void show(Fraction r)
    {
        r=reduction(r);
        if(r.up<0)
        {
          printf("(");
        }    
        if(r.down==1)printf("%lld",r.up);
        else if(abs(r.up)>r.down)
        {
          printf("%lld %lld/%lld",r.up/r.down,abs(r.up)%r.down,r.down);
        }else 
        {
           printf("%lld/%lld",r.up,r.down);
        }
        if(r.up<0)
        {
          printf(")");
        }  
    
    }
    int main(int argc, char* argv[])
    {
    
        scanf("%lld/%lld %lld/%lld",&a.up,&a.down,&b.up,&b.down);
        show(a);printf(" + ");show(b);printf(" = ");show(add(a,b));printf("
    ");
        show(a);printf(" - ");show(b);printf(" = ");show(minusF(a,b));printf("
    ");
        show(a);printf(" * ");show(b);printf(" = ");show(multi(a,b));printf("
    ");
        show(a);printf(" / ");show(b);printf(" = ");
    
        if(b.up==0)printf("Inf");
        else show(divide(a,b));printf("
    ");
        system("pause"); 
        return 0;
    }
  • 相关阅读:
    Hz赫兹的定义
    NetCore 迅速接入微信支付+支付宝支付 payLink C# 交差并集
    C# 生产随机数 --几乎可以做到不重复
    Spark MLib完整基础入门教程
    (转)Scrapy 教程
    (转)python自顶向下设计步骤_python实现自顶向下,自底向上
    (转)scrapy架构图与执行流程
    (转)Python:字典(zip, dict)
    (转)APUE第13章 守护进程Deameon
    (转)Python开发指南
  • 原文地址:https://www.cnblogs.com/ligen/p/4335699.html
Copyright © 2011-2022 走看看