

一道数学题,乘以ai - aj 用平方差,O(n)解决
#include<bits/stdc++.h>
#define MAX 300010
using namespace std;
typedef long long ll;
ll a[MAX];
int main()
{
ios::sync_with_stdio(false);
ll n,p,k;
cin >> n >> p >> k;
for(int i=1; i<=n; i++){
cin >> a[i];
a[i]=(a[i]*a[i]%p*a[i]%p*a[i]%p-k*a[i]%p+p)%p;
}
sort(a + 1, a + n + 1);
ll temp = 0, ans = 0;
for(int i = 2; i <= n; i++){
if(a[i-1] == a[i]){
temp++;
ans+=temp;
}
else temp=0;
}
cout << ans << endl;
return 0;
}