
递归算法easy题
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* mergeTrees(TreeNode* t1, TreeNode* t2) {
if(t1 == NULL) {
return t2;
}
if(t2 == NULL) {}
return t1;
}
auto ans = new TreeNode(t1->val + t2->val);
ans->left = mergeTrees(t1->left, t2->left);
ans->right = mergeTrees(t1->right, t2->right);
return ans;
}
};