Given two binary strings, return their sum (also a binary string).
For example,
a = "11"
b = "1"
Return "100".
思路:跟大数加法差点儿相同。
class Solution {
public:
string addBinary(string a, string b) {
stack<int> s;
int na = a.size() - 1;
int nb = b.size() - 1;
int c = 0;
while (na > -1 || nb > -1) {
int va = 0;
if (na > -1) {
va = a[na] - '0';
na--;
}
int vb = 0;
if (nb > -1) {
vb = b[nb] - '0';
nb--;
}
int tmp = va + vb + c;
c = tmp / 2;
s.push(tmp % 2);
}
if (c != 0) s.push(c);
string ans;
while (!s.empty()) {
ans.push_back(s.top()+'0');
s.pop();
}
return ans;
}
};