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  • UVA


    两个暴力题。。


    题目传送:11827 Maximum GCD


    AC代码:

    #include <map>
    #include <set>
    #include <cmath>
    #include <deque>
    #include <queue>
    #include <stack>
    #include <cstdio>
    #include <cctype>
    #include <string>
    #include <vector>
    #include <cstdlib>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    #define LL long long
    #define INF 0x7fffffff
    using namespace std;
    
    int a[105];
    
    int gcd(int a, int b) {
    	return b == 0 ? a : gcd(b, a % b);
    }
    
    int main() {
    	int T;
    	scanf("%d", &T);
    	getchar();
    	while(T --) {
    		int cnt = 0;
    		char s[100005];
    		gets(s);
    		int len = strlen(s);
    		for(int i = 0; i < len; i ++) {
    			if(s[i] != ' ') {
    				int tmp = 0; 
    				for(; isdigit(s[i]); i ++) {
    					tmp = tmp * 10 + s[i] - '0';
    				}
    				a[cnt ++] = tmp;
    			}
    		}
    		
    		int ans = 0;
    		for(int i = 0; i < cnt; i ++) {
    			for(int j = i + 1; j < cnt; j ++) {
    				ans = max(ans, gcd(a[i], a[j]));
    			}
    		}
    		
    		printf("%d
    ", ans);
    	}
    	return 0;
    }
    





    题目传送:10200 Prime Time


    AC代码:

    #include <map>
    #include <set>
    #include <cmath>
    #include <deque>
    #include <queue>
    #include <stack>
    #include <cstdio>
    #include <cctype>
    #include <string>
    #include <vector>
    #include <cstdlib>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    #define LL long long
    #define INF 0x7fffffff
    using namespace std;
    
    int biao[10005];
    
    bool isPrime(int x) {
    	if(x == 2 || x == 3) return true;
    	int m = (int)sqrt(x + 0.5);
    	for(int i = 2; i <= m; i ++) {
    		if(x % i == 0) return false;
    	}
    	return true;
    }
    
    void init() {
    	for(int i = 0; i < 40; i ++) {
    		biao[i] = 1;
    	}
    	for(int i = 40; i < 10005; i ++) {
    		int t = i * i + i + 41;
    		if(isPrime(t)) {
    			biao[i] = 1;
    		}
    		else biao[i] = 0;
    	}
    }
    
    int main() {
    	init();
    	int a, b;
    	while(scanf("%d %d", &a, &b) != EOF) {
    		int cnt = 0;
    		for(int i = a; i <= b; i ++) {
    			cnt += biao[i];
    		}
    		printf("%.2lf
    ", (cnt * 1.0) / (b - a + 1) * 100.0 + 1e-6);//注意浮点数误差 
    	}
    	return 0;
    }
    














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  • 原文地址:https://www.cnblogs.com/liguangsunls/p/6795080.html
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