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  • 数组去重、数组中的对象去重

    // 数组去重
    {
       const arr = [1,2,3,4,1,23,5,2,3,5,6,7,8,undefined,null,null,undefined,true,false,true,‘中文‘,‘‘,‘‘,‘hello‘,‘中文‘];
       //  第一种
       const r = [...new Set(arr)];
       console.log(r); // [1, 2, 3, 4, 23, 5, 6, 7, 8, undefined, null, true, false, "中文", "", "hello"]
    
       
       // 第二种
       const R = arr.reduce((all,name) => all.includes(name) ? all :[...all,name],[]);
       console.log(R); // [1, 2, 3, 4, 23, 5, 6, 7, 8, undefined, null, true, false, "中文", "", "hello"]
       
       // 第三种
       const k = arr.filter((item, i) => i === arr.indexOf(item));
       console.log(k); // [1, 2, 3, 4, 23, 5, 6, 7, 8, undefined, null, true, false, "中文", "", "hello"]
    }
    
    
    // 统计每个元素在数组中出现的次数
    {
       const arr = [‘zhangsan‘, ‘lisi‘, ‘wangwu‘, ‘zhangsan‘, ‘lisi‘, ‘wangwu‘,‘zhaosi‘,‘liuneng‘];
       const r = arr.reduce((all, name) =>{
          if(name in all){
             all[name]++
          }else{
             all[name] = 1;
          }
          return all;
       },{});
       console.log(r); // {zhangsan: 2, lisi: 2, wangwu: 2, zhaosi: 1, liuneng: 1}
    }
    
    // 数组对象去重
    {
       const arr = [
          {
             name:‘zhangsan‘,
                age:12
          },
            {
             name:‘lisi‘,
             age:14
          },
          {
             name:‘zhangsan‘,
                age:12
          },
            {
             name:‘lisi‘,
             age:14
          },
          {
             name:‘zhangsan‘,
                age:12
          },
            {
             name:‘lisi‘,
             age:14
          },
          {
             name:‘zhangsan‘,
                age:12
          },
            {
             name:‘wangwu‘,
             age:16
          },
          {
             name:‘wagnwu‘,
                age:16
          },
            {
             name:‘lisi‘,
             age:14
          },
          
       ]
       
       // 根据 age 去重
        // 方法一
        const age = ‘age‘;
       const r = arr.reduce((all, next) => all.some((atom) => atom[age] == next[age]) ? all : [...all, next],[]);
       console.log(r);
    
    }
    

      

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  • 原文地址:https://www.cnblogs.com/lilelile/p/11350962.html
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