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  • iOS- UITextView禁止Emoji表情

     UITextView代理方法:判断

    -(void)textViewDidEndEditing:(UITextView *)textView{
            if ([self stringContainsEmoji:self.feedbackTextView.text]) {
                UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"不能带有表情符号,请输入中文" message:nil delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
                [alertView show];
            }
    }

    #pragma mark 判断NSString字符串是否包含emoji表情
    - (BOOL)stringContainsEmoji:(NSString *)string{

        __block BOOL returnValue = NO;
        
        [string enumerateSubstringsInRange:NSMakeRange(0, [string length])
                                   options:NSStringEnumerationByComposedCharacterSequences
                                usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
                                    const unichar hs = [substring characterAtIndex:0];
                                    if (0xd800 <= hs && hs <= 0xdbff) {
                                        if (substring.length > 1) {
                                            const unichar ls = [substring characterAtIndex:1];
                                            const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
                                            if (0x1d000 <= uc && uc <= 0x1f77f) {
                                                returnValue = YES;
                                            }
                                        }
                                    } else if (substring.length > 1) {
                                        const unichar ls = [substring characterAtIndex:1];
                                        if (ls == 0x20e3) {
                                            returnValue = YES;
                                        }
                                    } else {
                                        if (0x2100 <= hs && hs <= 0x27ff) {
                                            returnValue = YES;
                                        } else if (0x2B05 <= hs && hs <= 0x2b07) {
                                            returnValue = YES;
                                        } else if (0x2934 <= hs && hs <= 0x2935) {
                                            returnValue = YES;
                                        } else if (0x3297 <= hs && hs <= 0x3299) {
                                            returnValue = YES;
                                        } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) {
                                            returnValue = YES;
                                        }
                                    }
                                }];
        
        return returnValue;

    }

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  • 原文地址:https://www.cnblogs.com/linxiu-0925/p/5379247.html
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