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  • Leetcode | Roman to Integer & Integer to Roman

    Roman to Integer

    Given a roman numeral, convert it to an integer.

    Input is guaranteed to be within the range from 1 to 3999.

    搜了一下,才知道这道题可以写这么简洁。

     1 class Solution {
     2 public:
     3     int romanToInt(string s) {
     4         if (s.empty()) return 0;
     5         int dict[100];
     6         dict['I'] = 1; dict['V'] = 5; dict['X'] = 10; dict['L'] = 50;
     7         dict['C'] = 100; dict['D'] = 500; dict['M'] = 1000;
     8     
     9         int ans = dict[s[0]];
    10         for (int i = 1; i < s.length(); ++i) {
    11             if (dict[s[i]] <= dict[s[i - 1]]) {
    12                 ans += dict[s[i]];
    13             } else {
    14                 ans = ans - 2 * dict[s[i - 1]] + dict[s[i]];
    15             }
    16         }
    17         return ans;
    18     }
    19 };

    Integer to Roman

    Given an integer, convert it to a roman numeral.

    Input is guaranteed to be within the range from 1 to 3999.

     1 class Solution {
     2 public:
     3     string intToRoman(int num) {
     4         string str[] = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
     5         int value[] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
     6         
     7         string ret = "";
     8         for (int i = 0; i < 13; ++i) {
     9             while (num >= value[i]) {
    10                 ret += str[i];
    11                 num -= value[i];
    12             }
    13         }
    14         return ret;
    15     }
    16 };
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  • 原文地址:https://www.cnblogs.com/linyx/p/3986686.html
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