题目传送门
解题思路:
就是一个比较奇特的混合背包,每种情况单独处理就好了
AC代码:
1 #include<iostream> 2 #include<cstdio> 3 4 using namespace std; 5 6 int n,m,w[101],c[101],a[101],id[101],f[2001]; 7 8 int main() { 9 scanf("%d%d",&n,&m); 10 for(int i = 1;i <= n; i++) { 11 scanf("%d",&id[i]); 12 if(id[i] == 1) 13 scanf("%d%d",&w[i],&c[i]); 14 if(id[i] == 2) 15 scanf("%d%d%d",&c[i],&w[i],&a[i]); 16 if(id[i] == 3) 17 scanf("%d%d",&c[i],&w[i]); 18 } 19 for(int i = 1;i <= n; i++) { 20 if(id[i] == 1) 21 for(int j = m;j >= 0; j--) 22 for(int k = j;k >= 0; k--) 23 f[j] = max(f[j],f[k] + w[i] * (j - k) * (j - k) - c[i] * (j - k)); 24 if(id[i] == 2) 25 for(int k = 1;k <= a[i]; k++) 26 for(int j = m;j >= w[i]; j--) 27 f[j] = max(f[j],f[j-w[i]] + c[i]); 28 if(id[i] == 3) 29 for(int j = w[i];j <= m; j++) 30 f[j] = max(f[j],f[j-w[i]] + c[i]); 31 } 32 printf("%d",f[m]); 33 return 0; 34 }