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  • Leetcode-Climbing Stairs

    You are climbing a stair case. It takes n steps to reach to the top.

    Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

    Analysis:

    d[i] = d[i-1]+d[i-2]. i steps is the way of reaching i-1 steps + the way of reaching i-2 steps.

    Solution:

     1 public class Solution {
     2     public int climbStairs(int n) {
     3         if (n==0) return 0;
     4         if (n==1) return 1;
     5         if (n==2) return 2;
     6     
     7         int first = 1;
     8         int second = 2;
     9         for (int i=3;i<=n;i++){
    10             int newVal = first+second;
    11             first=second;
    12             second = newVal;
    13         }
    14 
    15         return second;
    16         
    17     }
    18 }
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  • 原文地址:https://www.cnblogs.com/lishiblog/p/4129890.html
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