zoukankan      html  css  js  c++  java
  • LeetCode-Implement Queue using Stacks

    Implement the following operations of a queue using stacks.

    • push(x) -- Push element x to the back of queue.
    • pop() -- Removes the element from in front of queue.
    • peek() -- Get the front element.
    • empty() -- Return whether the queue is empty.

    Notes:

      • You must use only standard operations of a stack -- which means only push to top, peek/pop from top, size, and is empty operations are valid.
      • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
      • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

    Analysis:

    Maintain a push stack and a pop stack. For pop(), if pop stack is empty, we move all elements in push stack into pop stack. After that, we can always pop until pop stack is empty.

    Solution:

    class MyQueue {
        Stack<Integer> pushQ = new Stack<Integer>();
        Stack<Integer> popQ = new Stack<Integer>();
        
        // Push element x to the back of queue.
        public void push(int x) {
            pushQ.push(x);
        }
    
        // Removes the element from in front of queue.
        public void pop() {
            peek();
            popQ.pop();
        }
    
        // Get the front element.
        public int peek() {
            if (popQ.isEmpty())
                while (!pushQ.empty()){
                    popQ.push(pushQ.pop());
                }
            return popQ.peek();
        }
    
        // Return whether the queue is empty.
        public boolean empty() {
            return popQ.empty() && pushQ.empty();
        }
    }
  • 相关阅读:
    VBScript 函数
    C#创建activex供js调用
    java调用jni
    vbscript基本语法
    javascript 与vbscript 互相调用
    java调用jni
    mysql 无权限修改user 【修改root密码问题】
    vbscript基本语法
    js九九乘法表
    100~999之间的水仙花数
  • 原文地址:https://www.cnblogs.com/lishiblog/p/5870456.html
Copyright © 2011-2022 走看看