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  • BZOJ 1015 星球大战(并查集)

    正着不好搞,考虑倒着搞。倒着搞就是一个并查集。

    # include <cstdio>
    # include <cstring>
    # include <cstdlib>
    # include <iostream>
    # include <vector>
    # include <queue>
    # include <stack>
    # include <map>
    # include <set>
    # include <cmath>
    # include <algorithm>
    using namespace std;
    # define lowbit(x) ((x)&(-x))
    # define pi acos(-1.0)
    # define eps 1e-3
    # define MOD 1000000007
    # define INF (LL)1<<60
    # define mem(a,b) memset(a,b,sizeof(a))
    # define FOR(i,a,n) for(int i=a; i<=n; ++i)
    # define FO(i,a,n) for(int i=a; i<n; ++i)
    # define bug puts("H");
    # define lch p<<1,l,mid
    # define rch p<<1|1,mid+1,r
    # define mp make_pair
    # define pb push_back
    typedef pair<int,int> PII;
    typedef vector<int> VI;
    # pragma comment(linker, "/STACK:1024000000,1024000000")
    typedef long long LL;
    int Scan() {
        int res=0, flag=0;
        char ch;
        if((ch=getchar())=='-') flag=1;
        else if(ch>='0'&&ch<='9') res=ch-'0';
        while((ch=getchar())>='0'&&ch<='9')  res=res*10+(ch-'0');
        return flag?-res:res;
    }
    void Out(int a) {
        if(a<0) {putchar('-'); a=-a;}
        if(a>=10) Out(a/10);
        putchar(a%10+'0');
    }
    const int N=400005;
    //Code begin...
     
    int edge[N][2], node[N], fa[N], res[N];
    bool vis[N];
    VI head[N];
     
    int find(int x)
    {
        int s, temp;
        for (s=x; fa[s]>=0; s=fa[s]) ;
        while (s!=x) temp=fa[x], fa[x]=s, x=temp;
        return s;
    }
    void union_set(int x, int y)
    {
        int temp = fa[x]+fa[y];
        if (fa[x]>fa[y]) fa[x]=y, fa[y]=temp;
        else fa[y]=x, fa[x] = temp;
    }
    int main ()
    {
        int n, m, p;
        mem(fa,-1);
        scanf("%d%d",&n,&m);
        FOR(i,1,m) scanf("%d%d",&edge[i][0],&edge[i][1]);
        scanf("%d",&p);
        int ans=n-p;
        FOR(i,1,p) scanf("%d",node+i), vis[node[i]]=1;
        FOR(i,1,m) {
            if (vis[edge[i][0]]) head[edge[i][0]].pb(edge[i][1]);
            if (vis[edge[i][1]]) head[edge[i][1]].pb(edge[i][0]);
            if (!vis[edge[i][0]] && !vis[edge[i][1]]) {
                int u=find(edge[i][0]), v=find(edge[i][1]);
                if (u!=v) union_set(u,v), --ans;
            }
        }
        res[p+1]=ans;
        for (int i=p; i>=1; --i) {
            int u=node[i];
            for (int j=0; j<head[u].size(); ++j) {
                if (vis[head[u][j]]) continue;
                int v=find(u), w=find(head[u][j]);
                if (v!=w) union_set(v,w), --ans;
            }
            ++ans;
            res[i]=ans;
            vis[u]=0;
        }
        FOR(i,1,p+1) printf("%d
    ",res[i]);
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/lishiyao/p/6480589.html
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