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  • PAT Advanced 1050 String Subtraction (20分)

    Given two strings S1​​ and S2​​, S=S1​​S2​​ is defined to be the remaining string after taking all the characters in S2​​ from S1​​. Your task is simply to calculate S1​​S2​​ for any given strings. However, it might not be that simple to do it fast.

    Input Specification:

    Each input file contains one test case. Each case consists of two lines which gives S1​​ and S2​​, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

    Output Specification:

    For each test case, print S1​​S2​​ in one line.

    Sample Input:

    They are students.
    aeiou
    
     

    Sample Output:

    Thy r stdnts.

    这题考了差集,用unordered_map进行判别会节省一点时间

    #include <iostream>
    #include <unordered_map>
    using namespace std;
    unordered_map<char, bool> m;
    int main() {
        string str, pattern, res;
        getline(cin, str);
        getline(cin, pattern);
        for(int i = 0; i < pattern.length(); i++) m[pattern[i]] = 1;
        for(int i = 0; i < str.length(); i++)
            if(!m[str[i]]) res += str[i];
        cout << res;
        system("pause");
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/littlepage/p/12221187.html
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