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  • obj对象数据归类整理

    两个字段根据id对应整理
     
     
    <!doctype html>
    <html lang="en">
    <head>
        <meta charset="UTF-8">
        <title>两个字段根据id对应整理</title>
    </head>
    <body>
    <script>
    var data ={
        clation:[
            {name: "高尔夫·纯电", parentid: "21"},
            {name: "宝来·纯电",   parentid: "21"},
            {name: "蔚领C-TREK",  parentid: "1"},
            {name: "高尔夫 · 嘉旅",parentid: "1"},
            {name: "宝来·传奇"  ,parentid: "1"},
            {name: "宝来"   ,parentid: "1"},
            {name: "高尔夫"   ,parentid: "1"},
            {name: "全新一代速腾"   ,parentid: "1"},
            {name: "迈腾"   ,parentid: "2"},
            {name: "CC"   ,parentid: "2"},
            {name: "探歌T-ROC"   ,parentid: "3"},
            {name: "探影TACQUA"   ,parentid: "3"},
            {name: "新迈腾"   ,parentid: "2"},
            {name: "探歌T-ROC"   ,parentid: "3"},
        ],
        level: [
            {id: "3", name: "SUV"},
            {id: "21", name: "新能源"},
            {id: "2", name: "中型车"},
            {id: "1", name: "紧凑车型"},
        ]
    }
    var clation = data.clation;
    var level = data.level;
    console.log(data,'before') 
    var arr = [];
    for (var i = 0; i < level.length; i++) {
        if(level[i].id){
            var obj = {};
            obj.title = level[i].name;
            obj.list = clation.filter(function(e){
                return (e.parentid ==level[i].id)
            })
            arr.push(obj)
        } 
    }
    //反选arr.reverse()
    console.log(arr,'after')
    </script>
    </body>
    </html>
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  • 原文地址:https://www.cnblogs.com/liubingyjui/p/12744287.html
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