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  • JSP第一周作业

    1.求1-100之间的偶数和?

    <%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
    <%
        String path = request.getContextPath();
        String basePath = request.getScheme() + "://"
                + request.getServerName() + ":" + request.getServerPort()
                + path + "/";
    %>
    
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
    <html>
    <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index.jsp' starting page</title>
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
    </head>
    
    <body>
        求1-100的偶数和?
        <hr>
        <br>
    </body>
    
    <%
        int a, sum = 0;
        for (a = 1; a <= 100; a++) {
            if (a % 2 == 0) {
                sum += a;
            }
        }
    %>
    
    1-100中间的偶数和是:
    <%=sum%>
    </html>

     

     2.求1-100之间的素数之和=?

    <%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
    <%
        String path = request.getContextPath();
        String basePath = request.getScheme() + "://"
                + request.getServerName() + ":" + request.getServerPort()
                + path + "/";
    %>
    
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
    <html>
    <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index.jsp' starting page</title>
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
    </head>
    
    <body>
        求1-100的素数和?
        <hr>
        <br>
    </body>
    
    <%
        int i, j, sum = 0;
        for (i = 1; i <= 100; i++) {
            for (j = 2; j < i; j++) {
                if (i % j == 0) {
                    break;
                }
            }
            if (j == i) {
                sum += i;
            }
        }
    %>
    1-100中间的素数和是:
    <%=sum%>
    </html>

     

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  • 原文地址:https://www.cnblogs.com/liujiayi123/p/14475584.html
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