zoukankan      html  css  js  c++  java
  • POJ 1276 Cash Machine -- 动态规划(背包问题)

    题目地址:http://poj.org/problem?id=1276

    Description

    A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses exactly N distinct bill denominations, say Dk, k=1,N, and for each denomination Dk the machine has a supply of nk bills. For example,

    N=3, n1=10, D1=100, n2=4, D2=50, n3=5, D3=10

    means the machine has a supply of 10 bills of @100 each, 4 bills of @50 each, and 5 bills of @10 each.

    Call cash the requested amount of cash the machine should deliver and write a program that computes the maximum amount of cash less than or equal to cash that can be effectively delivered according to the available bill supply of the machine.

    Notes:
    @ is the symbol of the currency delivered by the machine. For instance, @ may stand for dollar, euro, pound etc.

    Input

    The program input is from standard input. Each data set in the input stands for a particular transaction and has the format:

    cash N n1 D1 n2 D2 ... nN DN

    where 0 <= cash <= 100000 is the amount of cash requested, 0 <=N <= 10 is the number of bill denominations and 0 <= nk <= 1000 is the number of available bills for the Dk denomination, 1 <= Dk <= 1000, k=1,N. White spaces can occur freely between the numbers in the input. The input data are correct.

    Output

    For each set of data the program prints the result to the standard output on a separate line as shown in the examples below.

    Sample Input

    735 3  4 125  6 5  3 350
    633 4  500 30  6 100  1 5  0 1
    735 0
    0 3  10 100  10 50  10 10

    Sample Output

    735
    630
    0
    0


    #include <stdio.h>
    #include <string.h>
    
    #define MAX 100001
    #define MAXN 11
    #define Max(a, b) (a) > (b) ? (a) : (b)
    
    int cash;
    int num[MAXN];
    int deno[MAXN];
    int dp[MAX];
    
    void ZeroOnePack (int deno){
    	int i;
    	for (i=cash; i>=deno; --i)
    		dp[i] = Max(dp[i], dp[i-deno] + deno);
    }
    
    void CompletePack (int deno){
    	int i;
    	for (i=deno; i<=cash; ++i)
    		dp[i] = Max(dp[i], dp[i-deno] + deno);
    }
    
    void MultiplePack (int deno, int num){
    	if (deno * num >= cash)
    		CompletePack (deno);
    	else{
    		int k = 1;
    		while (k < num){
    			ZeroOnePack (deno * k);
    			num -= k;
    			k *= 2;
    		}
    		ZeroOnePack (deno * num);
    	}
    }
    
    int main(void){
    	int N;
    	int i;
    
    	while (scanf ("%d%d", &cash, &N) != EOF){
    		for (i=1; i<=N; ++i){
    			scanf ("%d%d", &num[i], &deno[i]);
    		}
    		memset (dp, 0, sizeof(dp));
    		for (i=1; i<=N; ++i){
    			MultiplePack (deno[i], num[i]);
    		}
    		
    		printf ("%d
    ", dp[cash]);
    	}
    
    	return 0;
    }

    参考资料:背包问题九讲

  • 相关阅读:
    ecs云服务器 mysql经常自动停止挂掉重启问题分析
    mysql报错mmap(137428992 bytes) failed; errno 12,Cannot allocate memory for the buffer pool
    nodeJs的nodemailer发邮件报错hostname/IP doesn't match certificate's altnames怎么解决?
    js数组去重常用方法
    rsync远程数据同步工具的使用
    nginx报错 [error] open() “/usr/local/var/run/openresty.pid” failed (2: No such file or directory)
    webstorm使用问题总结
    正则表达式
    docker
    【转】90%的人会遇到性能问题,如何用1行代码快速定位
  • 原文地址:https://www.cnblogs.com/liushaobo/p/4373766.html
Copyright © 2011-2022 走看看