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  • zoj 3406 Another Very Easy Task

    Another Very Easy Task

    Time Limit: 2 Seconds      Memory Limit: 65536 KB

    This task is so easy that the description is omitted.

    Sample Input

    A numeronym is a number-based word.
    
    Most commonly, a numeronym is a word where a number is used to form an
    abbreviation  (albeit not an acronym or an initialism). Pronouncing the
    letters and numbers may sound similar to the full word: "K9" for "canine"
    (phonetically: "kay" + "nine"). A similar example in French is "K7" for
    "cassette" (phonetically: "ka" + "sept").
    
    Alternatively, the letters between the first and last are replaced by a
    number representing the number of letters omitted, such as "i18n" for
    "internationalization". Sometimes the last letter will also be counted
    and omitted.
    
    According to Tex Texin, the first numeronym of this kind was "S12n", the
    electronic mail account name given to DEC employee Jan Scherpenhuizen by
    a system administrator because his surname was too long to be an account
    name. Colleagues who found Jan's name unpronounceable often referred to
    him verbally as "S12n". The use of such numeronyms became part of DEC
    corporate culture.
    

    Sample Output

    A n7m is a n4r-b3d w2d.
    
    M2t c6y, a n7m is a w2d w3e a n4r is u2d to f2m an
    a10n  (a4t n1t an a5m or an i8m). P9g t1e
    l5s a1d n5s m1y s3d s5r to t1e f2l w2d: "K9" f1r "c4e"
    (p10y: "k1y" + "n2e"). A s5r e5e in F4h is "K7" f1r
    "c6e" (p10y: "ka" + "s2t").
    
    A11y, t1e l5s b5n t1e f3t a1d l2t a1e r6d by a
    n4r r10g t1e n4r of l5s o5d, s2h as "i18n" f1r
    "i18n". S7s t1e l2t l4r w2l a2o be c5d
    a1d o5d.
    
    A7g to T1x T3n, t1e f3t n7m of t2s k2d w1s "S12n", t1e
    e8c m2l a5t n2e g3n to D1C e6e J1n S12n by
    a s4m a11r b5e h1s s5e w1s t1o l2g to be an a5t
    n2e. C8s w1o f3d J1n's n2e u13e o3n r6d to
    h1m v6y as "S12n". T1e u1e of s2h n8s b4e p2t of D1C
    c7e c5e.

     1 #include <iostream>
     2 #include <cctype>
     3 #include <cstdio>
     4 #include <cstdlib>
     5 #include <cstring>
     6 #include <algorithm>
     7 using namespace std;
     8 char a[100000];
     9 int main(void){
    10 #ifndef ONLINE_JUDGE
    11   freopen("1.in", "r", stdin);
    12   freopen("1.out", "w", stdout);
    13 #endif
    14   while (gets(a)){
    15     int len = strlen(a); bool flag = false; int cnt = 0;
    16     for (int i = 0; i < len; ++i){
    17       cnt = 0; flag = false;
    18       while (isalpha(a[i])){
    19         if (!flag){
    20           flag = true; 
    21           printf("%c", a[i]);
    22         }
    23         else cnt++; 
    24         i++;
    25       }
    26       if (cnt == 1) printf("%c", a[i-1]);
    27       else if (cnt >= 2){printf("%d", cnt-1); printf("%c", a[i-1]);}
    28       if (i < len) printf("%c", a[i]);
    29     }
    30     printf("\n");
    31   }
    32   return 0;
    33 }

    这道水题,纠结好久,唉,真是思维不严谨啊,以后输出字符类的输出的题目一定要输出到文件,不然哪里错了都看不出来,水题还这么卡,看来自己需要练练手速,还有做题的准确度。

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  • 原文地址:https://www.cnblogs.com/liuxueyang/p/2970063.html
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