zoukankan      html  css  js  c++  java
  • POJ 1562 Oil Deposit经验教训

    Description

    The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzes each plot separately, using sensing equipment to determine whether or not the plot contains oil. A plot containing oil is called a pocket. If two pockets are adjacent, then they are part of the same oil deposit. Oil deposits can be quite large and may contain numerous pockets. Your job is to determine how many different oil deposits are contained in a grid.

    Input

    The input contains one or more grids. Each grid begins with a line containing m and n, the number of rows and columns in the grid, separated by a single space. If m = 0 it signals the end of the input; otherwise 1 <= m <= 100 and 1 <= n <= 100. Following this are m lines of n characters each (not counting the end-of-line characters). Each character corresponds to one plot, and is either `*', representing the absence of oil, or `@', representing an oil pocket.

    Output

    are adjacent horizontally, vertically, or diagonally. An oil deposit will not contain more than 100 pockets.

    Sample Input

    1 1
    *
    3 5
    *@*@*
    **@**
    *@*@*
    1 8
    @@****@*
    5 5 
    ****@
    *@@*@
    *@**@
    @@@*@
    @@**@
    0 0

    Sample Output

    0
    1
    2
    2
    其实是一道水题,我却纠结了半个多小时。原因是样例输入数据居然有问题,红色处5 5后跟了一个空格,按理说该直接跟换行,这导致用gets()输入的话会输入错误数据。
    while(scanf("%d%d",&row,&col)&&row)
    {
        getchar();
        for(int i=0;i<row;++i)
        {
            gets(Map[i]);
            //printf("This Map[%d],len=%d\n",i,strlen(Map[i]));
            //puts(Map[i]);
        }
    }


    上面是对本题来说错误的输入代码,其他题目正确。但以后最好小心使用,因为下面的输入代码虽然慢,却十分有效,不容易出错。

    while(scanf("%d%d",&row,&col)&&row)
        {
            Read();
            ...
            ...
        }
    void Read()
    {
        char c;
        for(int i=0;i<row;++i)
        {
            for(int j=0;j<col;++j)
            {
                cin>>c;
                if(c=='*')
                {
                    use[i][j]=false;
                }
                else
                {
                    use[i][j]=true;
                }
            }
        }
    }

    以后一定要记住:对换行符输入的处理尽量用C++的输入,不容易出错。

    善用C的大神可以无视。

  • 相关阅读:
    Asp.net性能优化总结(一)
    Visual C#常用函数和方法集汇总
    ASP.net下大文件上传的解决方案及WebbUpload组件源码
    正则表达式学习
    在Asp.net中为图像加入版权信息
    Cognos 维度函数
    Cognos8.3函数使用手册(二)
    cognos更新步聚
    Cognos8.3函数使用手册(一)
    Cognos 8 报表备份和恢复
  • 原文地址:https://www.cnblogs.com/liuyalunuli/p/POJ_1562_Oil_Deposits.html
Copyright © 2011-2022 走看看