iOS中文网址路径转换URLEncode

今天发现一个蛋疼的问题，服务端返回的urlString里面有时含有中文,使用

[NSURL URLWithString:urlString]生成URL对象时,iOS客户端不能正确进行网络请求,网上找到的URLEncode方法又不能完全解决问题.

方法1:

NSString* encodedString = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

 

方法2:

NSString * encodedString = (NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,(CFStringRef)urlString,NULL,NULL,kCFStringEncodingUTF8);

这两种方法当urlString里含有中文时URL编码是正确的,但是如果其中含有已转义的%等符号时,又会再次转义而导致错误.

 

查看方法2参数说明:

CFStringRef CFURLCreateStringByAddingPercentEscapes(CFAllocatorRef allocator, CFStringRef originalString, CFStringRef charactersToLeaveUnescaped, CFStringRef legalURLCharactersToBeEscaped, CFStringEncoding encoding);

 

因此做出修改,写出方法:

NSString *encodedString = (NSString *)

CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,

                                        (CFStringRef)urlString,

                                        (CFStringRef)@"!$&'()*+,-./:;=?@_~%#[]",

                                        NULL,

                                        kCFStringEncodingUTF8);

如果在所有的类里都要用到这个方法,可以写成category,然后在头文件import "NSString+URL.h" 即可调用.

 

 

@interface NSString (URL)  
- (NSString *)URLEncodedString;  
@end  

#import "NSString+URL.h"  
  
@implementation NSString (URL)  
  
- (NSString *)URLEncodedString  
{  
    NSString *encodedString = (NSString *)  
    CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,  
                                            (CFStringRef)self,  
                                            (CFStringRef)@"!$&'()*+,-./:;=?@_~%#[]",  
                                            NULL,  
                                            kCFStringEncodingUTF8);  
    return encodedString;  
}  
@end  

 

调用方法: 

    NSString *encodedString = [urlString URLEncodedString];

    //encodedString do something