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  • Oracle 身份证校验

    SELECT SUBSTR('&AI', 0, 17) ||
    TRANSLATE(DECODE(MOD(SUM(SUBSTR(WI,
    REGEXP_INSTR(WI, ' ', 1, I) + 1,
    REGEXP_INSTR(WI, ' ', 1, I + 1) -
    REGEXP_INSTR(WI, ' ', 1, I) - 1) *
    SUBSTR(AI, I, 1)),
    11),
    10,
    'a',
    MOD(SUM(SUBSTR(WI,
    REGEXP_INSTR(WI, ' ', 1, I) + 1,
    REGEXP_INSTR(WI, ' ', 1, I + 1) -
    REGEXP_INSTR(WI, ' ', 1, I) - 1) *
    SUBSTR(AI, I, 1)),
    11)),
    '0123456789a',
    '10X98765432')
    FROM (SELECT '&AI' AI,
    ' 7 9 10 5 8 4 2 1 6 3 7 9 10 5 8 4 2 ' WI,
    ROWNUM I
    FROM DUAL
    CONNECT BY ROWNUM < 18);

    SELECT SUBSTR('&AI', 0, 17) ||
    TRANSLATE(DECODE(MOD(SUM(MOD(POWER(2, 18 - I), 11) *
    SUBSTR(AI, I, 1)),
    11),
    10,
    'a',
    MOD(SUM(MOD(POWER(2, 18 - I), 11) * SUBSTR(AI, I, 1)),
    11)),
    '0123456789a',
    '10X98765432')
    FROM (SELECT '&AI' AI, ROWNUM I FROM DUAL CONNECT BY ROWNUM < 18);

    SELECT SUBSTR('&AI', 0, 17) ||
    REPLACE(MOD(12 -
    MOD(SUM(MOD(POWER(2, 18 - I), 11) * SUBSTR(AI, I, 1)),
    11),
    11),
    '10',
    'X')
    FROM (SELECT '&AI' AI, ROWNUM I FROM DUAL CONNECT BY ROWNUM < 18);

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  • 原文地址:https://www.cnblogs.com/liuyitan/p/6203192.html
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