121-344. 反转字符串

关于这个执行的效率问题,同样的代码每次执行都有差别,所以不用在意

class Solution(object):

    """
    344. 反转字符串
    编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
    """
    def reverseString1(self, s):
        """
        :type s: List[str]
        :rtype: Non
        """
        s[:] = s[::-1]
        return s

    def reverseString(self, s):
        """
        :type s: List[str]
        :rtype: Non
        """
        length = len(s)
        i = 0
        j = length - 1
        while i < j:
            s[i], s[length - 1 - i] = s[length - 1 - i], s[i]
            i += 1
            j -= 1
        return s

    def reverseString2(self, s):
        """
        :type s: List[str]
        :rtype: None Do not return anything, modify s in-place instead.
        """

        for i in range(len(s) >> 1):
            s[i] = chr(ord(s[i]) + ord(s[-1 - i]))
            s[-1 - i] = chr(ord(s[i]) - ord(s[-1 - i]))
            s[i] = chr(ord(s[i]) - ord(s[-1 - i]))

    def reverseString3(self, s):
        """
        :type s: List[str]
        :rtype: None Do not return anything, modify s in-place instead.
        """
        t = ' '
        for i in range(len(s) // 2):
            t = ord(s[i])
            s[i] = s[-1 - i]
            s[-1 - i] = chr(t)


if __name__ == '__main__':
    s1 = Solution()
    nums = ["h","e","l","l","o"]
    print(s1.reverseString(nums))