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  • 宠物收养所

    题目描述

    思路

    代码

    #include <cstdio>
    #include <cstdlib>
    #include <ctime>
    #include <cmath>
    
    const int MAX = 8e4 + 5, mod = 1e6;
    int n, m, inf = 0x3f3f3f3f;
    int ans, rt, tot;
    bool flag;
    struct Node {
    	int lc, rc, key, pri, cnt, size;
    	#define lc(x) t[x].lc
    	#define rc(x) t[x].rc
    	#define key(x) t[x].key
    	#define pri(x) t[x].pri
    	#define cnt(x) t[x].cnt
    	#define size(x) t[x].size
    } t[MAX];
    
    inline int read() {
    	int s = 0, f = 1;
    	char ch = getchar();
    	while (ch < '0' || ch > '9') {
    		if (ch == '-') f = -1;
    		ch = getchar();
    	}
    	while (ch >= '0' && ch <= '9') s = s * 10 + ch - '0', ch = getchar();
    	return s * f;
    }
    void write(int x) {
    	if (x > 9) write(x / 10);
    	putchar(x % 10 + '0');
    }
    void update(int r) { size(r) = size(lc(r)) + size(rc(r)) + cnt(r); }
    void zig(int &r) {
    	int s = lc(r);
    	lc(r) = rc(s);
    	rc(s) = r;
    	size(s) = size(r);
    	update(r);
    	r = s;
    }
    void zag(int &r) {
    	int s = rc(r);
    	rc(r) = lc(s);
    	lc(s) = r;
    	size(s) = size(r);
    	update(r);
    	r = s;
    }
    void insert(int &r, int k) {
    	if (!r) {
    		r = ++tot, key(r) = k, pri(r) = rand();
    		cnt(r) = size(r) = 1, lc(r) = rc(r) = 0;
    		return;
    	} else ++size(r);
    	if (k == key(r)) ++cnt(r);
    	else if (k < key(r)) {
    		insert(lc(r), k);
    		if (pri(lc(r)) < pri(r)) zig(r);
    	} else {
    		insert(rc(r), k);
    		if (pri(rc(r)) < pri(r)) zag(r);
    	}
    }
    
    void del(int &r, int k) {
    	if (key(r) == k) {
    		if (cnt(r) >= 2) --cnt(r), --size(r);
    		else if(!lc(r) || !rc(r)) r = lc(r) + rc(r);
    		else if(pri(lc(r)) < pri(rc(r))) zig(r), del(r, k);
    		else zag(r), del(r, k);
    		return;
    	} 
    	--size(r);
    	if (k < key(r)) del(lc(r), k);
    	else del(rc(r), k);
    }
    
    int queryPre(int k) {
    	int r = rt, res = inf;
    	while (r) {
    		if (key(r) <= k) res = key(r), r = rc(r);
    		else r = lc(r);
    	}
    	return res;
    }
    int queryNxt(int k) {
    	int r = rt, res = inf;
    	while (r) {
    		if (k < key(r)) res = key(r), r = lc(r);
    		else r = rc(r);
    	}
    	return res;
    }
    
    int queryKth(int k) {
    	int r = rt, res = inf;
    	while (r) {
    		if (size(lc(r)) < k && size(lc(r)) + cnt(r) >= k) return key(r);
    		else if(size(lc(r)) >= k) r = lc(r); 
    		else k -= size(lc(r)) + cnt(r), r = rc(r);
    	}
    	return res;
    }
    
    int queryRand(int k) {
    	int r = rt, res = 0;
    	while (r) {
    		if (k == key(r)) return size(lc(r)) + cnt(r) + 1;
    		else if (k < key(r)) r = lc(r); 
    		else res += size(lc(r)) + cnt(r), r = rc(r);   
    	}
    	return res;
    }
    void show(int x) {
    	printf("%d %d %d %d
    ", lc(x), rc(x), key(x), pri(x));
    	if (lc(x) != 0) show(lc(x));
    	if (rc(x) != 0) show(rc(x));
    }
    int main() {
    	n = read();
    	srand(time(NULL));
    	// write(n), putchar('
    ');
    	for (int i = 1, a, b, p, q, j; i <= n; ++i) {
    		a = read(), b =read();
    		// printf("%d %d
    ", a, b);
    		if (a == 0) {
    			if (flag) insert(rt, b);
    			else {
    				if (!flag && rt == 0) insert(rt, b), flag = true;
    				else {
    					j = inf;
    					p = queryPre(b), q = queryNxt(b);
    					if (p != inf) j = b - p;
    					if (q != inf && q - b < j) j = q - b;
    					if (j != inf) ans = ((long long)ans + j % mod) % mod;
    					if (p != inf && j == b - p) del(rt, p); 
    					else if(q != inf && j == q - b) del(rt, q);
    				}
    			} 
    		} else if (a == 1) {
    			if (!flag) insert(rt, b);
    			else {
    				if (flag && rt == 0) insert(rt, b), flag = false;
    				else {
    					j = inf;
    					p = queryPre(b), q = queryNxt(b);
    					if (p != inf) j = b - p;
    					if (q != inf && q - b < j) j = q - b;
    					if (j != inf) ans = ((long long)ans + j % mod) % mod;
    					if (p != inf && j == b - p) del(rt, p); 
    					else if(q != inf && j == q - b) del(rt, q);
    				}
    			}
    		}
    	}
    	write(ans);
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/liuzz-20180701/p/11546100.html
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