iOS通过代码来实现退出应用程序

之前一直没有遇到过需要直接在程序中退出应用程序的情况，今天有这个需求，我在网上查了一下，代码如下

// 退出当前程序
- (void)exitApplication {
    
    [UIView beginAnimations:@"exitApplication" context:nil];
    
    [UIView setAnimationDuration:0.5];
    
    [UIView setAnimationDelegate:self];
    
    // [UIView setAnimationTransition:UIViewAnimationCurveEaseOut forView:self.view.window cache:NO];
    
    [UIView setAnimationTransition:UIViewAnimationTransitionCurlDown forView:self.view cache:NO];
    
    [UIView setAnimationDidStopSelector:@selector(animationFinished:finished:context:)];
    
    //self.view.window.bounds = CGRectMake(0, 0, 0, 0);
    
    self.view.bounds = CGRectMake(0, 0, 0, 0);
    
    [UIView commitAnimations];
    
}

- (void)animationFinished:(NSString *)animationID finished:(NSNumber *)finished context:(void *)context {
    
    if ([animationID compare:@"exitApplication"] == 0) {
        
        exit(0);
        
    }

 其实只需要一句哈就可以了  ，如果嫌麻烦的话可以直接使用

exit(0);