select:
想在查询结果中加一点列:select id,'good' from table a;
把一列结果集横过来:select listagg(EMAIL_ALIAS,'@cisco.com,') within group (order by EMAIL_ALIAS) OWNER from (结果集);
把数据弄成树形结构:select SYS_CONNECT_BY_PATH(ar.acct_resource_name,'*/') full_path ('*/' 为连接符号)
from ACCT_RESOURCE ar
start with ar.ACCT_RESOURCE_PARENT_ID in (76145125, 29128165) (以这两个节点为父节点的)
connect by prior ar.acct_resource_id = ar.ACCT_RESOURCE_PARENT_ID (prior的那边代表父节点)