《程序员代码面试指南》第二章 链表问题 合并两个有序的单链表

样例

head1：2 4 6 8 10，head2：1 3 5 7 9，结果：1 2 3 4 5 6 7 8 9 10 

java代码

/**
 * @Description:合并两个有序的单链表
 * @Author: lizhouwei
 * @CreateDate: 2018/4/7 17:27
 * @Modify by:
 * @ModifyDate:
 */
public class Chapter2_19 {

    public Node mergeSortLink(Node head1, Node head2) {
        if (head1 == null || head2 == null) {
            return head1 == null ? head2 : head1;
        }
        Node head = null;
        Node pre = null;
        Node next = null;
        Node cur1 = null;
        Node cur2 = null;
        head = head1.vlaue < head2.vlaue ? head1 : head2;
        cur1 = head1.vlaue < head2.vlaue ? head1 : head2;
        cur2 = head1.vlaue < head2.vlaue ? head2 : head1;
        while (cur1 != null && cur2 != null) {
            if (cur1.vlaue < cur2.vlaue) {
                pre = cur1;
                cur1 = cur1.next;
            } else {
                next = cur2.next;
                pre.next = cur2;
                cur2.next = cur1;
                pre = cur2;
                cur2 = next;
            }
        }
        pre.next = cur2 != null ? cur2 : cur1;
        return head;
    }

    //测试
    public static void main(String[] args) {
        Chapter2_19 chapter = new Chapter2_19();
        Link link1 = new Link();
        Link link2 = new Link();

        //构造链表
        for (int i = 10; i > 0; i=i-2) {
            link1.add(i);
        }
        for (int i = 9; i > 0; i=i-2) {
            link2.add(i);
        }
        Link.printLink(link1.head);
        Link.printLink(link2.head);
        Node head = chapter.mergeSortLink(link1.head, link2.head);
        Link.printLink(head);
    }
}