办公自动化15-一次性生成多层目录

excel里面的目录是这样的：

生成的目录是这样的

代码如下：

import os, sys
import pandas as pd 

path = 'C:/Users/17360/Desktop/cy/' 

df = pd.read_excel(r'C:Users17360Desktop	est.xlsx',sheet_name= 'Sheet1')#将excel表中的文件夹名称读入DataFrame

df.head()


menu = list(df['目录'])
for lst in menu:
    print(lst)
    num = lst.split(' ')[0]#分条件，生成文件夹
　　　　
    if len(num.split("-")) == 2:
        file_name = path + str(lst) #文件夹路径
        os.mkdir(file_name) #生成文件夹
    if len(num.split("-")) == 3:
        if (len(num.split('-')[1])+len(num.split('-')[0])) == 2:
            pat = re.compile('^'+num[0:3]+'[^d]*[u4e00-u9fa5]+')
        if (len(num.split('-')[1]) + len(num.split('-')[0])) == 3:
            pat = re.compile('^'+num[0:4]+'[^d]*[u4e00-u9fa5]+')
        if len(num.split('-')[1]) == 2&len(num.split('-')[0]) == 2:
            pat = re.compile('^'+num[0:5]+'[^d]*[u4e00-u9fa5]+')
        for i in menu:
            tem = pat.findall(i)
            print(tem)
            if len(tem)>0:
                file_name = path +str(tem[0]) + '/' + str(lst) #文件夹路径
                os.mkdir(file_name) #生成文件夹
    if len(num.split("-")) == 4:
        if len(num.split('-')[1]) == 1:
            pat = re.compile('^'+num[0:3]+'[^d]*[u4e00-u9fa5]+')
        if (len(num.split('-')[1]) + len(num.split('-')[0])) == 3:
            pat = re.compile('^'+num[0:4]+'[^d]*[u4e00-u9fa5]+')
        if len(num.split('-')[1]) == 2&len(num.split('-')[0]) == 2:
            pat = re.compile('^'+num[0:5]+'[^d]*[u4e00-u9fa5]+')
        
        if (len(num.split('-')[1]) + len(num.split('-')[0])+len(num.split('-')[2])) == 3:
            pat1 = re.compile('^'+num[0:5]+'[^d]*[u4e00-u9fa5]+')
        if (len(num.split('-')[1]) + len(num.split('-')[0])+len(num.split('-')[2])) == 4:
            pat1 = re.compile('^'+num[0:6]+'[^d]*[u4e00-u9fa5]+')
        if (len(num.split('-')[1]) + len(num.split('-')[0])+len(num.split('-')[2])) == 5:
            pat1 = re.compile('^'+num[0:7]+'[^d]*[u4e00-u9fa5]+')
        if (len(num.split('-')[1]) + len(num.split('-')[0])+len(num.split('-')[2])) == 6:
            pat1 = re.compile('^'+num[0:8]+'[^d]*[u4e00-u9fa5]+')
             
     
        for i in menu:
            tem = pat.findall(i)
            if len(tem)>0:
                s1 = tem
                print(s1)
        for i in menu:
            tem1 = pat1.findall(i)
            if len(tem1)>0:
                s2 = tem1
                print(s2)
         
        file_name = path +str(s1[0])+'/'+str(s2[0]) + '/' + str(lst) #文件夹路径
        os.mkdir(file_name) #生成文件夹

有问题欢迎提问哦~~~^_^