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  • 二叉树的前中后层遍历

    package com.data.tree;
    
    public class BiTree {
        String data;//数据域
        BiTree left,right;//下一个结点
        int leval;//层数
    }
    package com.data.tree;
    
    /**
     * ClassName TreeTest Description TODO
     * @author Payphone
     * @date 2018年12月24日 下午1:44:07
     * @version V1.0
     */
    public class TreeTest {
        public static int maxsize = 100;
    
        public static void main(String[] args) {// 创建二叉树
            String[] arr = { "A", "B", "C", "D", "E", "#", "#", "#", "#", "#", "#" };
    
            TreeTest ts = new TreeTest();
            BiTree tree = ts.createTree(new BiTree(), arr);
            ts.levelOrder(tree);
            System.out.println(tree.toString());
        }
    
        /**
         * @Title createTree
         * @Description 层序建二叉树
         * @param bt
         * @param node
         * @return BiTree
         */
        BiTree createTree(BiTree bt, String[] node) {
            int rear = -1, front = -1;
            BiTree[] queue = new BiTree[maxsize];// 定义队列
            int flag = 0;// 数组下标
            bt = new BiTree();
            bt.data = node[flag++];// 给根节点赋值
            queue[++rear] = bt;// 根节点入队
            // 数组未读取完毕且队列非空时
            while (flag < node.length && !(rear == front)) {
                BiTree b = queue[++front];
                // 给出队的节点 创建左子树
                if (node[flag] == "#") {
                    b.left = null;
                    flag++;
                } else {
                    b.left = new BiTree();
                    b.left.data = node[flag++];
                    // 左子树非空则入队
                    queue[++rear] = b.left;
                } // end if
                    // 给出队的节点创建右子树
                if (node[flag] == "#") {
                    b.right = null;
                    flag++;
                } else {
                    b.right = new BiTree();
                    b.right.data = node[flag++];
                    // 右子树非空入队
                    queue[++rear] = b.right;
                } // end if
            }
            return bt;
        }
    
        /**
         * @Title levelOrder
         * @Description 
         *         二叉树的层序遍历
         *         节点出队打印 左右子树入队
         * @param tree
         * @return void
         */
        public void levelOrder(BiTree tree) {
            int rear = -1,front = -1;
            BiTree[] queue = new BiTree[maxsize];
            queue[++rear] = tree;
            while(rear!=front) {
                BiTree bt = queue[++front];
                System.out.println(bt.data);
                if(bt.left!=null) {
                    queue[++rear] = bt.left;
                }
                if(bt.right!=null) {
                    queue[++rear] = bt.right;
                }
            }
        }
        
        
        //先序遍历
        public void PreNode(BiTree tree) {
            if (tree != null) {
                System.out.println(tree.data);
                PreNode(tree.left);
                PreNode(tree.right);
            }
        }
    
        /*
         * 先序遍历思想: 先把左子树一直入栈 左子树到头了在从栈中弹出元素 看弹出的元素是否有右节点 有就继续按先序来
         */
        public void PreNodeUn(BiTree tree) {
            int top = -1;
            BiTree[] stack = new BiTree[maxsize];
            while (top != -1 || tree != null) {
                if (tree != null) {
                    System.out.println(tree.data);
                    stack[++top] = tree;
                    tree = tree.left;
                } else {
                    tree = stack[top--];
                    tree = tree.right;
                }
            }
        }
    
        public void PreNodeUn1(BiTree tree) {
            int top = -1;
            BiTree[] stack = new BiTree[maxsize];
            while (top != -1 || tree != null) {
                while (tree != null) {
                    System.out.println(tree.data);
                    stack[++top] = tree;
                    tree = tree.left;
                }
                if (tree == null) {
                    tree = stack[top--];
                    tree = tree.right;
                }
            }
        }
    
        // 中序遍历
        public void InOrder(BiTree tree) {
            InOrder(tree.left);
            System.out.println(tree.data);
            InOrder(tree.right);
        }
    
        // 中序遍历
        public void InOrderUn(BiTree tree) {
            int top = -1;
            BiTree[] stack = new BiTree[maxsize];// 定义栈
            while (top != -1 || tree != null) {
                while (tree != null) {
                    stack[++top] = tree;
                    tree = tree.left;
                }
                if (tree == null) {
                    tree = stack[top--];
                    System.out.println(tree.data);
                    tree = tree.right;
                }
            }
        }
    
        // 后序遍历
        void PostOrder(BiTree tree) {
            PostOrder(tree.left);
            PostOrder(tree.right);
            System.out.println(tree.data);
        }
    
        // 后序非递归
        void PostOrderUn(BiTree tree) {
            BiTree flag = null;
            int top = -1;
            BiTree[] stack = new BiTree[maxsize];
            while (top != -1 || tree != null) {
                while (tree != null) {// 左子树一直入栈
                    stack[++top] = tree;
                    tree = tree.left;
                }
                // 左子树访问到头了
                if (tree == null) {
                    tree = stack[top];// 获取栈顶 看其是否有右子树
                    if (tree.right != null && tree.right != flag) {// 有右子树且未被访问过
                        tree = tree.right;// 以右子树为根继续进行其左子树的入栈操作
                    } else {// 左右都已经访问完毕了。[第一次访问的一定是叶子节点,它没有左右子树]
                        System.out.println(tree.data);
                        top--;// 元素出栈
                        flag = tree;// flag表示已经访问了。
                        tree = null;// 让下一个元素出栈
                    }
                }
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/ljwdemo/p/10168467.html
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