编写一个函数来查找字符串数组中的最长公共前缀。
如果不存在公共前缀,返回空字符串 ""。
示例 1:
输入:strs = ["flower","flow","flight"]
输出:"fl"
示例 2:
输入:strs = ["dog","racecar","car"]
输出:""
解释:输入不存在公共前缀。
提示:
0 <= strs.length <= 200
0 <= strs[i].length <= 200
strs[i] 仅由小写英文字母组成
1.
class Solution(object): def longestCommonPrefix(self, strs): """ :type strs: List[str] :rtype: str """ mi=min(strs,key=len) l=len(mi) mi=list(mi) for i in range(l): for i in range(len(strs)): if "".join(mi) != strs[i][:len(mi)]: del mi[-1] break return "".join(mi)
2.
class Solution(object): def longestCommonPrefix(self, strs): """ :type strs: List[str] :rtype: str """ mi=min(strs,key=len) l=len(mi) mi=list(mi) K=[] for i in range(l): for j in range(len(strs)): if mi[i]!=strs[j][i]: return "".join(K) break K.append(mi[i]) return "".join(K)
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/longest-common-prefix