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  • hdu 1690

    #include <stdio.h>
    #include <string.h>
    #include <algorithm>
    using namespace std;
    #define N 1005
    #define INF 200000000000
    #define LL __int64
    LL ma[N][N],d[N],vis[N],dis[N];
    LL dijkstral(LL v0,LL n,LL t)
    {
        LL v,x,y,temp,i;
        for(i = 1 ; i <= n ; i++)
        {
            d[i] = ma[v0][i];
            vis[i] = 0;
        }
        d[v0] = 0;
        vis[v0] = 1;
        for(i = 1 ; i <= n ; i++)
        {
            temp = INF;
            for(y = 1 ; y <= n ;y++)
                if(!vis[y]&&temp>d[y]) temp = d[x=y];
                if(temp == INF) return d[t];
            vis[x] = 1;
            for(y = 1 ; y <= n ; y++)
                if(!vis[y]&&d[x]+ma[x][y]<d[y])
                d[y] = d[x]+ma[x][y];
        }
        return d[t];
    }
    int main()
    {
        LL n,m,i,j,k,s,ed,L1,L2,L3,L4,C1,C2,C3,C4,t,cas = 1;
        scanf("%I64d",&t);
        while(t--)
        {
            scanf("%I64d %I64d %I64d %I64d %I64d %I64d %I64d %I64d",&L1,&L2,&L3,&L4,&C1,&C2,&C3,&C4);
            scanf("%I64d %I64d",&n,&m);
            for(i = 1; i <= n ; i++)
                scanf("%I64d",&dis[i]);
            for(i = 1 ; i <= n ; i++)
                for(j = i+1 ; j <= n ; j++)
            {
               LL ans = abs(dis[i]-dis[j]);
                if(ans>0&&ans<=L1) ma[i][j] = ma[j][i] = C1;
                else if(ans>L1&&ans<=L2) ma[i][j] = ma[j][i] = C2;
                else if(ans>L2&&ans<=L3) ma[i][j] = ma[j][i] = C3;
                else if(ans>L3&&ans<=L4) ma[i][j] = ma[j][i] = C4;
                else ma[i][j] = ma[j][i] = INF;
            }
            printf("Case %d:
    ",cas++);
                while(m--)
                {
                   scanf("%I64d %I64d",&s,&ed);
                   LL res = dijkstral(s,n,ed);
                    if(res!=INF)
                    printf("The minimum cost between station %I64d and station %I64d is %I64d.
    ",s,ed,res);
                    else printf("Station %I64d and station %I64d are not attainable.
    ",s,ed);
                }
    
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/llei1573/p/3912923.html
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