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  • 【打CF,学算法——二星级】Codeforces Round #313 (Div. 2) B. Gerald is into Art(水题)

    【CF简单介绍】

    提交链接:http://codeforces.com/contest/560/problem/B


    题面:

    B. Gerald is into Art
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of ana1 × b1 rectangle, the paintings have shape of aa2 × b2 anda3 × b3 rectangles.

    Since the paintings are painted in the style of abstract art, it does not matter exactly how they will be rotated, but still, one side of both the board, and each of the paintings must be parallel to the floor. The paintings can touch each other and the edges of the board, but can not overlap or go beyond the edge of the board. Gerald asks whether it is possible to place the paintings on the board, or is the board he bought not large enough?

    Input

    The first line contains two space-separated numbers a1 andb1 — the sides of the board. Next two lines contain numbersa2, b2, a3 andb3 — the sides of the paintings. All numbersai, bi in the input are integers and fit into the range from1 to 1000.

    Output

    If the paintings can be placed on the wall, print "YES" (without the quotes), and if they cannot, print "NO" (without the quotes).

    Sample test(s)
    Input
    3 2
    1 3
    2 1
    
    Output
    YES
    
    Input
    5 5
    3 3
    3 3
    
    Output
    NO
    
    Input
    4 2
    2 3
    1 2
    
    Output
    YES
    
    Note

    That's how we can place the pictures in the first test:

    And that's how we can do it in the third one.

    解题:

        就是看能不能把两块画。放进板内,要求画必须平行于板。


    代码:

    #include <iostream>
    #include <algorithm>
    #include <cstdio>
    using namespace std;
    int main()
    {
        int l1,w1,l2,w2,l3,w3;
        scanf("%d%d",&l1,&w1);
        scanf("%d%d",&l2,&w2);
        scanf("%d%d",&l3,&w3);
        bool flag=false;
        if((l2+l3)<=l1&&(w2<=w1&&w3<=w1))
          flag=true;
        else if((l2+w3)<=l1&&(w2<=w1)&&(l3<=w1))
          flag=true;
        else if((w2+l3)<=l1&&(l2<=w1)&&(w3<=w1))
          flag=true;
        else if((w2+w3)<=l1&&(l2<=w1&&l3<=w1))
          flag=true;
        else if((w2+w3)<=w1&&(l2<=l1)&&(l3<=l1))
          flag=true;
        else if((w2+l3)<=w1&&(l2<=l1)&&(w3<=l1))
          flag=true;
        else if((l2+w3)<=w1&&(w2<=l1)&&(l3<=l1))
          flag=true;
        else if((l2+l3)<=w1&&(w2<=l1)&&(w3<=l1))
          flag=true;
          if(flag)printf("YES
    ");
          else printf("NO
    ");
        return 0;
    } 



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  • 原文地址:https://www.cnblogs.com/llguanli/p/6761259.html
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