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  • CF div2 320 A

    A. Raising Bacteria
    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    You are a lover of bacteria. You want to raise some bacteria in a box.

    Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly x bacteria in the box at some moment.

    What is the minimum number of bacteria you need to put into the box across those days?

    Input

    The only line containing one integer x (1 ≤ x ≤ 109).

    Output

    The only line containing one integer: the answer.

    Sample test(s)
    input
    5
    output
    2
    input
    8
    output
    1
    Note

    For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.

    For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1.

    水题

     1 #include <cstdio>
     2 #include <cstring>
     3 #include <iostream>
     4 #include <queue>
     5 #include <stack>
     6 #include <vector>
     7 #include <algorithm>
     8 
     9 using namespace std;
    10 
    11 const int maxn = 100005;
    12 
    13 typedef long long ll;
    14 
    15 
    16 
    17 int main()
    18 {
    19     long long n;
    20     scanf("%lld",&n);
    21     long long cnt = 1;
    22 
    23     while(n!=1){
    24         if(n%2==0) n/=2;
    25         else {
    26             n--;
    27             cnt++;
    28         }
    29 
    30     }
    31     printf("%d
    ",cnt);
    32 
    33 
    34 
    35 
    36     return 0;
    37 }
    View Code
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  • 原文地址:https://www.cnblogs.com/lmlyzxiao/p/4817987.html
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