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  • 代码实现:有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数

    //有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数
    import java.util.ArrayList;
    import java.util.Scanner;
    
    public class Test36 {
    	public static void main(String[] args) {
    		int n = getN();
    		int[] a = getNum(new int[n]);
    		int m = getM(n);
    		ArrayList<Integer> list = new ArrayList<>();
    		for (int i = 0; i < a.length; i++) {
    			list.add(a[i]);
    		}
    		for (int i = 0; i <= m; m--) {	
    			list.add(list.get(i));
    			list.remove(0);		
    		}
    		for (Integer integer : list) {
    			System.out.print(integer+" ");
    		}
    	}
    
    	public static int getM(int n) {
    		int m = 0 ;
    		while (true) {
    			m = getN();
    			if (m > n) {
    				System.out.println("输入大于" + n + "请重新输入");
    			}else{
    				return m ;
    			}
    		}
    	}
    
    	public static int[] getNum(int[] a) {
    		Scanner sc = new Scanner(System.in);
    		String s = "";
    		int i = 0;
    		System.out.println("请输入第1个整数:");
    		while (true) {
    			s = sc.nextLine();
    			try {
    				int num = Integer.parseInt(s);
    				a[i] = num;
    				i++;
    				if (i == a.length) {
    					break;
    				}
    				System.out.println("请输入第" + (i + 1) + "个整数:");
    			} catch (NumberFormatException e) {
    
    				System.out.println("输入非法,请重新输入");
    			}
    		}
    		return a;
    	}
    
    	public static int getN() {
    		int n = 0;
    		Scanner sc = new Scanner(System.in);
    		System.out.println("请输入一个数:");
    		while (true) {
    			String s = sc.nextLine();
    			try {
    				n = Integer.parseInt(s);
    				break;
    			} catch (NumberFormatException e) {
    				System.out.println("输入错误,请重新输入:");
    			}
    		}
    		return n;
    	}
    }
    
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  • 原文地址:https://www.cnblogs.com/loaderman/p/6527519.html
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