[LeetCode]题解（python）：80-Remove Duplicates from Sorted Array II

题目来源

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https://leetcode.com/problems/remove-duplicates-from-sorted-array-ii/

Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?

For example,
Given sorted array nums = [1,1,1,2,2,3],

Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn't matter what you leave beyond the new length.

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题意分析

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Input: type numsList[int]; 

Output: rtype int;

Conditions:删除array中的重复元素，但是允许重复次数为2，保证返回的length长度下包含所需值，大于length长度的元素不考虑

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题目思路

穷举思路，只要出现过两次，就将该元素忽略。其实因为数组是有序的，穷举效率肯定差一点，但是leetcode OJ通过了= =

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AC代码（Python）

class Solution(object):
    def removeDuplicates(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        
        k = 0
        l = len(nums)
        if l == 0:
            return 0
        for i in range(l):
            t = 0;
            for j in range(k):
                if nums[i] == nums[j]:
                    t+=1
            if t < 2:
                nums[k] = nums[i]
                k += 1
        #for i in range(k):
        #    print(str(nums[i]) + " ")
        return k