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  • 1114 Family Property

    This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average area and number of sets of their real estate.

    Input Specification:

    Each input file contains one test case. For each case, the first line gives a positive integer N (1000). Then N lines follow, each gives the infomation of a person who owns estate in the format:

    ID Father Mother Child1​​Childk​​ Mestate​​ Area

    where ID is a unique 4-digit identification number for each person; Father and Mother are the ID's of this person's parents (if a parent has passed away, -1 will be given instead); k (0k5) is the number of children of this person; Childi​​'s are the ID's of his/her children; Mestate​​ is the total number of sets of the real estate under his/her name; and Area is the total area of his/her estate.

    Output Specification:

    For each case, first print in a line the number of families (all the people that are related directly or indirectly are considered in the same family). Then output the family info in the format:

    ID M AVGsets​​ AVGarea​​

    where ID is the smallest ID in the family; M is the total number of family members; AVGsets​​ is the average number of sets of their real estate; and AVGarea​​ is the average area. The average numbers must be accurate up to 3 decimal places. The families must be given in descending order of their average areas, and in ascending order of the ID's if there is a tie.

    知识点:并查集

    注意并查集的写法

     1 #include <iostream>
     2 #include <algorithm>
     3 #include <vector>
     4 using namespace std;
     5 const int maxn = 10003;
     6 
     7 int ManSet[maxn];
     8 int Property[maxn][2];
     9 int used[maxn];
    10 //set<int>
    11 
    12 bool cmp(int a,int b){
    13     if(Property[a][1]/(-ManSet[a]+0.0)==Property[b][1]/(-ManSet[b]+0.0)){
    14         return a<b;
    15     }
    16     return Property[a][1]/(-ManSet[a]+0.0)>Property[b][1]/(-ManSet[b]+0.0);
    17 }
    18 
    19 int Find(int v){
    20     if(ManSet[v]<=-1){
    21         return v;
    22     }
    23     return ManSet[v] = Find(ManSet[v]);
    24 }
    25 
    26 int Unite(int n1, int n2){
    27     
    28     if(n1<n2){
    29         ManSet[n1] += ManSet[n2];
    30         ManSet[n2] = n1;
    31         return n1;
    32     }else{
    33         ManSet[n2] += ManSet[n1];
    34         ManSet[n1] = n2;
    35         return n2;
    36     }
    37 }
    38 
    39 int main(int argc, char *argv[]) {
    40     int n;
    41     fill(ManSet,ManSet+maxn,-1);
    42     fill(Property[0],Property[0]+maxn*2,0);
    43     fill(used,used+maxn,0);
    44     
    45     scanf("%d",&n);
    46     int man,fa,mo,k,tmpc,m,area;
    47     for(int i=0;i<n;i++){
    48         //printf("
    ");
    49         scanf("%d %d %d",&man,&fa,&mo);
    50         used[man] = used[fa] = used[mo] = 1;
    51         //printf("
    . %d %d,%d
    ",Find(man),i,n);
    52         man = Find(man); //printf("%d  ",man);
    53         if(fa!=-1){
    54             fa = Find(fa);
    55             if(fa!=man){
    56                 man = Unite(man,fa); //printf("%d ",man);
    57             }
    58         }
    59         man = Find(man);
    60         if(mo!=-1){
    61             mo = Find(mo);
    62             if(mo!=man){
    63                 man = Unite(man,mo);//printf("%d ",man);
    64             }
    65         }
    66         scanf("%d",&k);
    67         for(int j=0;j<k;j++){
    68             scanf("%d",&tmpc);
    69             used[tmpc] = 1;
    70             tmpc = Find(tmpc);
    71             man = Find(man);
    72             if(man!=tmpc){
    73                 man = Unite(man,tmpc);//printf("%d ",man);
    74             }
    75         }
    76         scanf("%d %d",&m,&area);
    77         Property[man][0] += m;
    78         Property[man][1] += area;
    79     }
    80     for(int i=0;i<maxn;i++){
    81         if(used[i]==1&&ManSet[i]>0&&Property[i][0]>0){
    82             int an = Find(i);
    83             Property[an][0]+=Property[i][0];
    84             Property[an][1]+=Property[i][1];
    85         }
    86     }
    87     vector<int> list;
    88     for(int i=0;i<maxn;i++){
    89         if(used[i]==1&&ManSet[i]<0){
    90             list.push_back(i);
    91             //printf("%04d %d %.3f %.3f
    ",i,(-ManSet[i]),Property[i][0]/(-ManSet[i]+0.0),Property[i][1]/(-ManSet[i]+0.0));
    92         }
    93     }
    94     sort(list.begin(), list.end(), cmp);
    95     printf("%d
    ",list.size());
    96     for(int i=0;i<list.size();i++){
    97         printf("%04d %d %.3f %.3f
    ",list[i],(-ManSet[list[i]]),Property[list[i]][0]/(-ManSet[list[i]]+0.0),Property[list[i]][1]/(-ManSet[list[i]]+0.0));
    98     }
    99 }
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  • 原文地址:https://www.cnblogs.com/lokwongho/p/9925345.html
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