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  • DB2 递归查询

    上一篇中讲解了ORACLE中的递归查询,下面我们看一下DB2中如何使用递归查询:

    同样的我们先新建一个表来存储以上信息,并插入测试数据:

    --建表
    create table FAMILY
    (
      person_id INTEGER,
      name      VARCHAR(10),
      parent_id INTEGER
    );
    --插入测试数据
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (1, 'Apple', 2);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (2, 'Zoe', 4);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (3, 'Tom', 4);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (4, 'John', 7);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (5, 'Peter', 6);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (6, 'Robert', 10);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (7, 'Mary', null);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (8, 'Jenny', 7);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (9, 'Sam', 10);
    
    insert into FAMILY (PERSON_ID, NAME, PARENT_ID) values (10, 'Li Lei', null);

    在DB2中使用with字句实现递归查询:

    WITH temp (person_id, name, parent_id, LEVEL)
         AS (SELECT person_id,
                    name,
                    parent_id,
                    0
               FROM FAMILY
              WHERE person_id = '1' --找寻person_id=1的人的祖先
             UNION ALL
             SELECT SUPER.person_id,
                    SUPER.name,
                    SUPER.parent_id,
                    CHILD.LEVEL + 1
               FROM FAMILY SUPER, temp CHILD
              WHERE SUPER.person_id = CHILD.parent_id)
    SELECT * FROM temp

    得到,如图我们可以得到Apple的父亲是Zoe,Zoe父亲是John,看level依次类推,Mary是他们老祖宗,

    当然,我们除了可以得到某个节点的父节点,

    WITH temp (person_id, name, parent_id, LEVEL)
         AS (SELECT person_id,
                    name,
                    parent_id,
                    1
               FROM FAMILY
              WHERE person_id = '4' --找寻person_id=4的人的祖先
             UNION ALL
             SELECT SUPER.person_id,
                    SUPER.name,
                    SUPER.parent_id,
                    CHILD.LEVEL + 1
               FROM FAMILY SUPER, temp CHILD
              WHERE SUPER.person_id = CHILD.parent_id)
    SELECT * FROM temp

    也可以得到某个节点的子节点:

    WITH temp (person_id, name, parent_id, LEVEL)
         AS (SELECT person_id,
                    name,
                    parent_id,
                    1
               FROM FAMILY
              WHERE person_id = '4' --找寻person_id=4的人的传人
             UNION ALL
             SELECT CHILD.person_id,
                    CHILD.name,
                    CHILD.parent_id,
                    SUPER.LEVEL + 1
               FROM FAMILY CHILD, temp SUPER
              WHERE SUPER.person_id = CHILD.parent_id)
    SELECT * FROM temp

    得到,其中Tom跟Zoe都是John的子节点。

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  • 原文地址:https://www.cnblogs.com/longjshz/p/5139730.html
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