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  • C语言指针理解

    C语言指针理解

    #include <stdio.h>
    int main(void){
    int zippo[4][2] = {{2,4},{6,8},{1,3},{5,7}};
    printf("    zippo = %p,    zippo + 1 = %p
    ",zippo,zippo +1);
    printf("    zippo[0] = %p,    zippo[0] + 1 = %p
    ",zippo[0],zippo[0] +1);
    printf("    *zippo = %p,    *zippo + 1 = %p
    ",*zippo,*zippo +1);
    printf("    zippo[0][0] = %d
    ",zippo[0][0]);
    printf("    **zippo =  %d
    ",**zippo);
    printf("    *zippo[0] = %d
    ",*zippo[0]);
    printf("    zippo[2][1] = %d
    ",zippo[2][1]);
    printf("    *(*(zippo + 2) + 1) = %d
    ",*(*(zippo + 2) + 1));
    printf("    zippo = %p,&zippo = %p,&zippo[0] = %p,zippo[0] = %p,&zippo[0][0] = %p,zippo[0][0] = %d
    ",zippo,&zippo,&zippo[0],zippo[0],&zippo[0][0],zippo[0][0]);
    
    printf("    *(*(zippo + 1) + 2) = %d,zippo[1][2] = %d
    ",*(*(zippo + 2) + 1),zippo[1][2]);
    printf("    &zippo[0][0] = %p,&zippo[0][1] = %p,&zippo[1][0] = %p,&zippo[1][1] = %p,&zippo[2][0] = %p,&zippo[2][1] = %p,&zippo[3][0] = %p,&zippo[3][1] = %p
    ",&zippo[0][0],&zippo[0][1],&zippo[1][0],&zippo[1][1],&zippo[2][0],&zippo[2][1],&zippo[3][0],&zippo[3][1]);
    return 0;
    
    }

    zippo 和 &zippo[0] 和 &zippo[0][0] 同一个地址 zippo[1][2] 因为C 不检查数组越界,所有zippo[1][2] 相当于 zipp0[2][0]

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  • 原文地址:https://www.cnblogs.com/loongqiang/p/3591136.html
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