【算法】模拟 【难度】☆☆☆☆☆
很简单的模拟题，关键是读清楚题，注意如何判断闰年。
View Code
1 /*
2 ID: wsc5001
3 LANG: C
4 TASK: friday
5 */
6 #include<stdio.h>
7 int runnian(int y)
8 {
9 if (y%100==0)
10 {
11 if (y%400==0)
12 return 1;
13 else
14 return 0;
15 }
16 if (y%4==0)
17 return 1;
18 }
19 int xingqi(int yu)
20 {
21 switch (yu)
22 {
23 case 0:return 6;
24 case 1:return 7;
25 default:return yu-1;
26 }
27 }
28 int main()
29 {
30 FILE *fin,*fout;
31 fin=fopen("friday.in","r");
32 fout=fopen("friday.out","w");
33 int i,j,n,runyear,tongji[8]={0},dayone=1,t;
34 fscanf(fin,"%d",&n);
35 for(i=0;i<n;i++)
36 {
37 runyear=runnian(1900+i);
38 for(j=1;j<=12;j++)
39 {
40 t=xingqi((dayone+13)%7);
41 tongji[t]+=1;
42 if(j==2)//二月
43 {
44 if (runyear==1)
45 dayone=xingqi(dayone+29+1); //闰年
46 else
47 dayone=xingqi(dayone+28+1);
48 }
49 else if(j==4||j==6||j==9||j==11)//小月
50 dayone=xingqi(dayone+30+1);
51 else//大月
52 dayone=xingqi(dayone+31+1);
53 }
54 }
55 fprintf(fout,"%d %d %d %d %d %d %d\n",tongji[6],tongji[7],tongji[1],tongji[2],tongji[3],tongji[4],tongji[5]);
56 //printf("%d %d %d %d %d %d %d\n",tongji[6],tongji[7],tongji[1],tongji[2],tongji[3],tongji[4],tongji[5]);
57 fclose(fin);
58 fclose(fout);
59 //getchar();
60 }