题目
求一个3*3矩阵主对角线元素之和。
import numpy as np
a = np.zeros((3,3))
for i in range(0,3):
for j in range(0,3):
a[i,j] = input('please input the number of index (%i,%i): '%(i,j))
item = [-2,-1,0,1,2];
for z in item:
su = 0
for i in range(0,3):
for j in range(0,3):
if i-j == z:
su = su + a[i,j]
print('(%i,%i) '%(i,j),end='')
print('Diagonal element addition: %0.2f'%su);