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  • c# 穷举

    //穷举
     int m=0;
                    for (int i = 1; i <=200/15; i++)
                    {
                        for (int j = 1; j <=200/3 ; j++)
                        {
                            for (int k = 1; k < 200/2; k++)
                            {
                                if (15*i+3*j+2*k==200)
                                {
                                    Console.WriteLine(i+"副拍子," + j + "个球,"+k+"瓶水;");
                                    m++;
                                }
                            }
                        }
                    }
                    Console.WriteLine("总共有"+m+"种可能");

                    Console.ReadKey();

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  • 原文地址:https://www.cnblogs.com/lovesy2413/p/4310590.html
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