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  • [ML]简单图像处理 (灰度图;图像压缩;信息隐藏)

    利用python的opencv2 库进行:

    jpg转bmp,

    jpg,bpm转灰度图,

    bmp质量(lossy)压缩,

    读取文本信息并转化为二进制隐藏于pixels

    # -*- coding: utf-8 -*-
    """
    Created on Fri Sep 20 10:20:25 2019
    
    @author: erio
    """
    
    import cv2 as cv
    import random
    import time
    
    #将jpg转换为bmp
    
    '''
    start = time.time()
    img = cv.imread('E:/2019HW_1.jpg', 1)
    cv.imwrite('E:/2019HW_1.bmp', img)
    end = time.time()
    print('JPG to BMP use %.5f s' %(end-start))
    
    
    #jpg和bmp转为灰度图
    
    start = time.time()
    img1 = cv.imread('E:/2019HW_1.jpg', 1)
    img1 = cv.cvtColor(img1, cv.COLOR_BGR2GRAY)
    cv.imwrite('E:/2019HW_1_gray.jpg', img1)
    end = time.time()
    print('JPG to GRAY use %.5f s' %(end-start))
    
    start = time.time()
    img2 = cv.imread('E:/2019HW_1.bmp', 1)
    img2 = cv.cvtColor(img2, cv.COLOR_BGR2GRAY)
    cv.imwrite('E:/2019HW_1_gray.bmp', img2)
    end = time.time()
    print('BMP to GRAY use %.5f s' %(end-start))
    '''
    
    '''
    #质量压缩
    for num in range(0,9):
        img = cv.imread('E:/2019HW_1.bmp', 1)
        na=100-10*num
        start = time.time()
        cv.imwrite('E:/lossy'+str(na)+'.jpg',img,[int(cv.IMWRITE_JPEG_QUALITY),100-num*10])
        end = time.time()
        print('lossy %d use %.5f s' %(100-num*10,end-start))
    
    '''
    
    # bmp格式RGB各8位,将字符串转化为二进制串后,每bit选取一个像素点的R层最后一位,变为str的二进制串
    
    # text为包含输入字符串的txt文件,src为原始bmp,output为隐藏信息的bmp文件名
    #return list x,y为隐藏了信息的pixels坐标
    def embed(text,src,output):
        #open()读文件中字符串 ord()将字符转ascii bin()转二进制 不足8bits的补全8bits。之后存储到strbin
        #strbin存储转换为8位二进制ascii的信息,lenth为strbin长度,也即信息总bit数
        f=open(text,'r',encoding='utf-8')
        res=f.read()
        #print(res)
        strbin=''
        lenth=0
        for c in res:
            k=bin(ord(c)).replace('0b', '')
            if len(k)<8:
                k='0'*(8-len(k))+k
            strbin=strbin+k
            lenth=lenth+8
        #strbin=strbin+'s'+(bin(ord(c)).replace('0b', ''))
        f.close()
        #读图并获得高度宽度
        img1 = cv.imread(src, 1)
        start = time.time()
        size=img1.shape
        width=size[1]
        height=size[0]
        #随机选取lenth个像素用于隐藏信息
        x=random.sample(range(1,width-1),lenth);  #选取了pixels的x,y坐标,不重复;
        y=random.sample(range(1,height-1),lenth);
        #print(type(x))                          #隐藏了信息的像素点坐标存在list x,y中
        # 通道分离,注意顺序BGR不是RGB
        #(B, G, R) = cv2.split(image)
        #提取R通道,在所选像素最后一位写入信息
        hideimg=cv.split(img1)[2]  
        for i in range(0,lenth):
            #print(hideimg[y[i],x[i]])
            #print(bin(hideimg[y[i],x[i]]))
            tmp=bin(hideimg[y[i],x[i]])
            tmp=tmp[0:-1]+strbin[i]
            #print(tmp)
            #print(strbin[i])
            rep=int(tmp,2)
            #print(rep)
            hideimg[y[i],x[i]]=rep   
        bimg=cv.split(img1)[0]               #src的B通道
        gimg=cv.split(img1)[1]
        # 将写入信息的R通道和原始BG通道合并
        merged=cv.merge([bimg,gimg,hideimg])
        cv.imwrite(output, merged)
        end = time.time()
        #print('use %.5f s' %(end-start))
        return x,y
    
    #hidebmp为隐藏了信息的文件名 list x,y为隐藏了信息的pixels坐标
    def extract(hidebmp,x,y):
        img1 = cv.imread('E:/merged.bmp', 1)    
        start = time.time()
        readimg=cv.split(img1)[2]
        output=''
        rang=int(len(x)/8) #隐藏信息字符个数
        #恢复信息
        for i in range(0,rang):
            result=''
            for j in range(0,8):
                k=i*8+j
                result=result+bin(readimg[y[k],x[k]])[-1]
            output=output+chr(int(result,2))
            #final=result.decode('utf-8')
        end = time.time()
        #print('use %.5f s' %(end-start))
        print(output)
    
    
    if __name__ == '__main__': 
        message='E:/names.txt'   #包含信息的TXT文件
        srcbmp='E:/2019HW_1.bmp' #原始bmp文件
        outputbmp='E:/merged.bmp' #隐藏了信息的bmp文件名
        x,y=embed(message,srcbmp,outputbmp)
        extract(outputbmp,x,y)
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  • 原文地址:https://www.cnblogs.com/lqerio/p/14812263.html
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