1.输入一个年份,判断是不是闰年(能被4整除但不能被100整除,或者能被400整除)
package demo01; import java.util.Scanner; public class demo001 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); System.out.print("请输入年份:"); int leap = input.nextInt(); if(((leap%4 == 0) && (leap%100 != 0)) || (leap%400 == 0)){ System.out.print(leap+"是闰年"); } else{ System.out.print(leap+"不是闰年"); } } }
2.输入一个4位会员卡号,如果百位数字是3的倍数,就输出是幸运会员,否则就输出不是.
package demo01; import java.util.Scanner; public class demo001 { public static void main(String[] args) { Scanner input=new Scanner(System.in); System.out.println("请输入四位会员卡号"); int a=input.nextInt(); switch(a%1000/100) { case 3: case 6: case 9: System.out.println("幸运会员");break; default: System.out.println("不是幸运会员");break; } } }
.已知函数,输入x的值,输出对应的y的值. x + 3 ( x > 0 ) y = 0 ( x = 0 ) x2 –1 ( x < 0 )
package demo01; import java.util.Scanner; public class demo001 { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("输入x:"); int x = input.nextInt(); if (x>0) { System.out.println("y="+(x+3)); }else if (x<0) { System.out.println("y="+(x*2-1)); }else { System.out.println("y=0"); } } }
输入三个数,判断能否构成三角形(任意两边之和大于第三边)
package demo01; import java.util.Scanner; public class demo001 { public static void main(String[] args) { Scanner input=new Scanner(System.in); System.out.println("请输入三个数"); int a=input.nextInt(); int b=input.nextInt(); int c=input.nextInt(); if(a+b>c&&a+c>b&&b+c>a) System.out.println("能够成三角形"); else System.out.println("不能构成三角形"); } }